Derivative of ln(x)

We know the derivative of ln(x), which is ¹⁄ₓ.

[ln(x)]' = ¹⁄ₓ

We can find the derivative of ln(x) using chain rule.

Find ᵈʸ⁄d, if

y = ln(x)

Let u = x.

y = ln(u)

Now,

y = ln(u) ----> y is a function of u

u = x ----> is is a function of x

By chain rule, the derivative of y with respect to x :

Substitute y = ln(u) and u = x.

Substitute u = x.

Therefore,

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