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We know the derivative of ln(x), which is ΒΉββ.
[ln(x)]' = ΒΉββ
We can find the derivative of ln(βx) using chain rule.
Find α΅ΚΈβdβ, if
y = ln(βx)
Let u = βx.
y = ln(u)
Now,
y = ln(u) ----> y is a function of u
u = βx ----> u is is a function of x
By chain rule, the derivative of y with respect to x :
Substitute y = ln(u) and u = βx.
Substitute u = βx.
Therefore,
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