We know the derivative of ex, which is ex.
(ex)' = ex
We can find the derivative of e√secx using chain rule.
Find ᵈʸ⁄dₓ, if
y = e√cotx
Let u = cotx.
y = e√u
Let v = √u.
y = ev
y = ev ----> y is a function of v
v = √u ----> v is is a function of u
u = cotx ----> u is is a function of x
By chain rule, the derivative of y with respect to x :
Substitute y = ev, v = √u and u = cotx.
Substitute v = √u.
Substitute u = cotx.
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