We know the derivative of ex, which is ex.
(ex)' = ex
We can find the derivative of esin√x using chain rule.
Find ᵈʸ⁄dₓ, if
y = ecos√x
Let u = √x.
y = ecosu
Let v = cosu.
y = ev
y = ev ----> y is a function of v
v = cosu ----> v is is a function of u
u = √x ----> u is is a function of x
By chain rule, the derivative of y with respect to x :
Substitute y = ev, v = cosu and u = √x.
Substitute v = cosu.
Substitute u = √x.
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