Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
De Morgan’s father (a British national) was in the service of East India Company, India. Augustus De Morgan (1806-1871) was born in Madurai, Tamilnadu, India. His family moved to England when he was seven months old. He had his education at Trinity college, Cambridge, England.
De Morgan’s laws relate the three basic set operations union, intersection and complement.
De morgan's law for set complementation :
Let U be the universal set containing sets A and B. Then
(i) (A u B)' = A' n B'
(ii) (A n B)' = A' u B'
(A n B)' = A' u B'


From the above Venn diagrams (2) and (5), it is clear that
(A n B)' = A' u B'
Hence, De morgan's law for complementation is verified.
(A U B)' = A' n B'


Example 1 :
Let U = {-2, -1, 0, 1, 2, 3, 4, 5, .......10 }, A = {-2, 2, 3, 4, 5} and B = {1, 3, 5, 8, 9}. Verify De Morgan’s laws of complementation
Solution :
First, we shall verify (A u B)' = A' n B'
To do this, we consider
A u B = {-2, 2, 3, 4, 5} u {1, 3, 5, 8, 9}
A u B = {-2, 1, 2, 3, 4, 5, 8, 9}
We know that
(A u B)' = U \ {-2, 1, 2, 3, 4, 5, 8, 9}
(A u B)' = {-1, 0, 6, 7, 10} -----(1)
A' = U \ A = U \ { -2, 2, 3, 4, 5 }
= {-1, 0, 1, 6, 7, 8, 9, 10}
B' = U \ B = U \ {1, 3, 5, 8, 9}
= {-2, -1, 0, 2, 4, 6, 7, 10}
A'nB' = {-1, 0, 1, 6, 7, 8, 9, 10} n {-2, -1, 0, 2, 4, 6, 7, 10}
A' n B' = {-1, 0, 6, 7, 10} -----(2)
From (1) and (2), it is clear that (A u B)' = A' n B'
First, we shall verify (A n B)' = A'u B'.
To do this, we consider
A n B = {- 2, 2, 3, 4, 5 } u {1, 3, 5, 8, 9}
A n B = {3, 5}
We know that
(A n B)' = U \ { 3, 5 }
(A n B)' = {2, -1, 0, 1, 2, 4, 6, 7, 8, 9, 10}
A' = U \ A = U \ {-2, 2, 3, 4, 5}
= {-1, 0, 1, 6, 7, 8, 9, 10}
B' = U \ B = U \ {1, 3, 5, 8, 9}
= {-2, -1, 0, 2, 4, 6, 7, 10}
A'UB' = {-1, 0, 1, 6, 7, 8, 9, 10} n {-2, -1, 0, 2, 4, 6, 7, 10}
A' U B' = {2, -1, 0, 1, 2, 4, 6, 7, 8, 9, 10} -----(2)
From (1) and (2), it is clear that
(A n B)' = A' U B'
Example 2 :
Let U = {4, 8, 12, 16, 20, 24, 28} , A = {8, 16, 24} and B = {4, 16, 20, 28}. Find (AU B)' and (A n B)'.
Solution :
A u B = {8, 16, 24} U {4, 16, 20, 28}
A u B = { 4, 8, 16, 20, 24, 28 }
We know that
(A u B)' = U \ { 4, 8, 16, 20, 24, 28 }
(A u B)' = { 12 }
(A n B) = {8, 16, 24} n {4, 16, 20, 28}
= {16}
(A n B)' = U \ { 16 }
= {4, 8, 12, 20, 24, 28}
Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
About Us | Contact Us | Privacy Policy
©All rights reserved. onlinemath4all.com

Dec 25, 25 08:30 AM
Dec 24, 25 07:58 PM
Dec 23, 25 11:34 PM