CURVED SURFACE AREA AND TOTAL SURFACE AREA OF SPHERE AND HEMISPHERE

Curved Surface Area and Total Surface Area of Sphere and Hemisphere :

Here we are going to see, some example problems of finding curved surface area and total surface area of sphere.

Formula for Curved Surface Area and Total Surface Area of Hemisphere

 Curved surface area  =  2Πr2Hollow hemisphere= 2Π(R2 + r2) sq. unitsTotal surface area of =  3Πr2Hollow hemisphere =  Π(3R2 + r2) sq. units

Curved Surface Area and Total Surface Area of hemisphere - Examples

Question 1 :

The radius of a sphere increases by 25%. Find the percentage increase in its surface area.

Solution :

Increased percentage of radius  =  125% of r

=  125r/100

=  5r/4

Surface area of hemisphere   =  2Πr2

Surface area of increased hemisphere   =  2Π(5r/4)2

=  25Πr2/8

=  [(25Πr2/8) - (2Πr2)]/(2Πr2)

=  9Πr2/8(2Πr2)

=  9Πr2/16 Πr2

=  0.5625

=  0.5625 (100)

=  56.25%

Question 2 :

The internal and external diameters of a hollow hemispherical vessel are 20 cm and 28 cm respectively. Find the cost to paint the vessel all over at 0.14 per cm2

Solution :

internal radius (r)  =  20/2  =  10 cm

External radius (R) =  28/2  =  14 cm

Curved surface area of hemisphere  = 2Π(R2 + r2

=  2 (22/7)(142 + 102)

=  2 (22/7)(196 + 100)

=  1860.57

Cost of painting  =  0.14 per cm2

Required cost  =  0.14 (1860.57)

=  260.48

Curved Surface Area and Total Surface Area of Frustum Cone

 C.S.A. of a frustum  =  Π(R +r)l sq. unitsT.S.A. of a frustum  =  Π(R + r)l + Π(R2+ r2)where, l = √[h2 +(R −r)2]

Question 3 :

Th e frustum shaped outer portion of the table lamp has to be painted including the top part. Find the total cost of painting the lamp if the cost of painting 1 sq.cm is 2.

Solution :

Curved surface area of lamp  =  Π(R +r)l sq. units

R = 12 m, r = 6 m and h = 8 m

l = √[h2 +(R −r)2]

l = √[82 +(12 −6)2]

l = √[64 + 62]

l = √(64 + 36)  √100

l = 10

C.S.A of frustum shaped lamp  =  Π(R +r)l

Area to be painted  =  Π(R +r)l + Πr2

=  (22/7)[(12 + 6)(10) + 62]

=  (22/7)[180+36]

=  678.85

Cost per sq.cm is 2

Required cost  =  678.85 (2)

=  1357.71

After having gone through the stuff given above, we hope that the students would have understood, "Curved Surface Area and Total Surface Area of Sphere and Hemisphere".

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