In this section, you will learn how to solve word problems on converting metric units.
Problem 1 :
David travels 60 kilometers in two hours. How many meters of distance will he cover in one minute ?
Solution :
Distance covered in 2 hours = 60 km
Distance covered in 1 hour = 30 km
We know that,
1 hour = 60 min
1 kilometer = 1000 meters
Given : David travels 60 km in two hrs
Then,
2 hours ----> 60 km
1 hour ----> (60/2) km
1 hour ----> 30 km
60 minutes ----> 30(1000) meters
60 minutes ----> 30000 meters
1 minute ----> (30000/60) meters
1 minute ----> 500 meters
Problem 2 :
Mark jogged 15840 meters in 45 minutes. Find the speed of Mark in meter per minute.
Solution :
Speed = Distance/Time
Speed = 15840/45
Speed = 352 meters per minute
Problem 3 :
Use a fraction to find the length in meters of a tile that is 9 centimeters long.
Solution :
Here, we convert smaller unit (centimeters) to bigger unit (meters).
So we have to divide.
We know that, 1 meter = 100 cm.
So, we have to use the fraction 1/100.
9 cm = 9(1/100) meters
9 cm = 9/100 meters
Problem 4 :
Kevin has a pole that is 24 meters tall. If Kevin sets the pole on a 300 centimeters stand, how far from the floor will the top of the pole be (in meters) ?
Solution :
Height of the pole = 24 meters
Height of the stand = 300 cm = (300/100)m = 3 m
Distance from the floor to the top of the pole is
= Height of the stand + Height of the pole
= 3 + 24
= 27 meters.
Problem 5 :
Becky and Keith each ran for exactly 20 minutes on a treadmill. Keith’s treadmill said that he had run 18500 meters. Becky’s treadmill said that she had run 2 kilometers. Who ran farther, and how much farther ?
Solution :
Both Becky and Keith took the same amount of time.
That is 20 minutes.
Distance covered by Becky and Keith are given in different units. (Meters and Kilometers)
We have to make the units same.
Convert meters in to kilometers.
Then,
18500 m = (18500/1000) km = 18.5 km
Therefore,
distance covered by Becky = 18.5 km ----(1)
distance covered by Keith = 2 km ----(2)
Difference between (1) and (2) is
= 18.5 - 2
= 16.5 km
Problem 6 :
David prepares 24 kilograms of metal in 1 hour 36 minutes. At the same rate, How many grams of metal will he prepare in one minute ?
Solution :
1 hr 36 min = 60 min + 36 min = 96 min
1 kg = 1000 grams
24 kg = 24(1000) grams = 24000 grams
Given : David prepares 24 kilograms of metal in 1 hour 36 minutes.
Then,
1 hr 36 min ----> 24 kg
96 min ----> 24000 grams
1 min ----> (24000/96) grams
1 min ----> 250 grams
Problem 7 :
Mark used 15840 grams of metal to make an alloy in 45 minutes. Find the amount metal used in one minute (in grams).
Solution :
Metal used in 45 minutes = 15840 grams
Metal used in 1 minute = (15840/45) grams
Metal used in 1 minute = 352 grams
Problem 8 :
Mrs. Moore handed out 40 grams of almonds to each of her 22 students . How many dekagrams of almonds did Mrs. Moore hand out ?
Solution :
Total no. of grams of almonds handed out is
= 4(22)
= 88
Here, we convert smaller unit (grams) into bigger unit (dekagrams).
So we have to divide.
We now that,
1 dekagram = 10 grams
Then, the total no. of dekagrams of almonds handed out is
= 88/10
= 8.8 dekagrams of almonds
Problem 9 :
Tommy uses 40 grams of cheese in each pizza he makes. How many kilograms of cheese does Tommy need to make 28 pizzas ?
Solution :
Given : Tommy uses 40 grams of cheese in each pizza he makes.
1 pizza ----> 40 grams of cheese
28 pizzas ----> 28 ⋅ 40 grams of cheese
28 pizzas ----> 1120 grams of cheese
28 pizzas ----> (1120/1000) kilograms of cheese
28 pizzas ----> 1.12 kilograms
Problem 10 :
A standard elevator in a mid rise building can hold a maximum weight of about 500 kilograms. Assuming an average adult weight of 70 kilograms, what is the maximum number of adults who could safely ride the elevator ?
Solution :
Given : Elevator can hold 500 kilograms.
If the average weight of an adult is 70 kilograms, then maximum no. of adults could safely ride the elevator is
= 500/70
= 7.14
≈ 7
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