Converting Metric Units Word Problems :
In this section, you will learn how to solve word problems step by step using conversions between different metric units.
Problem 1 :
David travels 60 kilometers in two hours. How many meters of distance will he cover in one minute ?
Distance covered in 2 hours = 60 kilometers
Distance covered in 1 hour = 30 kilometers
We know that,
1 hour = 60 minutes
1 kilometer = 1000 meters
Given : David travels 60 kilometers in two hours
2 hours -----> 60 km
1 hour -----> (60/2) km
1 hour -----> 30 km
60 minutes -----> (30 ⋅ 1000) meters
60 minutes -----> 30000 meters
1 minute -----> (30000/60) meters
1 minute -----> 500 meters
So, 500 meters of distance covered in 1 minute.
Problem 2 :
Mark jogged 15840 meters in 45 minutes. Find the speed of Mark in meter per minute.
Speed = Distance / Time
Speed = 15840/45
Speed = 352 meters per minute
So, the speed of Mark is 352 meters per minute.
Problem 3 :
Use a fraction to find the length in meters of a tile that is 9 centimeters long.
Here, we convert smaller unit (centimeters) into bigger unit (meters).
So we have to divide.
Because divide, we have to use the fraction 1/100.
We know that,
1 meter = 100 centimeters
9 centimeters = (9 ⋅ 1/100) meters
9 centimeters = 9/100 meters
So, 9 centimeters is equal to 9/100 meters.
Problem 4 :
Kevin has a pole that is 24 meters tall. If Kevin sets the pole on a 300 centimeters stand, how far from the floor will the top of the pole be (in meters) ?
Height of the pole = 24 meters
Height of the stand = 300 cm = (300/100) m = 3 m
Distance from the floor to the top of the pole is
= Height of the stand + Height of the pole
= 30 + 3
= 33 meters
So, the top of the pole is 33 meters far from the floor.
Problem 5 :
Becky and Keith each ran for exactly 20 minutes on a treadmill. Keith’s treadmill said he had run 18500 meters. Becky’s treadmill said she had run 2 kilometers. Who ran farther, and how much farther ?
Both Becky and Keith took the same amount of time.
That is 20 minutes.
Distance covered by Becky and Keith are given in different units. (Meters and Kilometers)
We have to make the units same.
Convert meters in to kilometers.
10000 m = (18500/1000) m = 18.5 km
Distance covered by Becky = 18.5 km -----(1)
Distance covered by Keith = 2 km -----(2)
Difference between (1) and (2) is
= 2 - 18.5
= 1.5 km
So, Becky ran farther by 1.5 km.
Problem 6 :
David prepares 24 kilograms of metal in 1 hour 36 minutes. At the same rate, How many grams of metal will he prepare in one minute ?
1 hr 36 min = 60 min + 36 min = 96 min
1 kg = 1000 grams
24 kg = 24 ⋅ 1000 grams = 24000 grams
Given : David prepares 24 kilograms of metal in 1 hour 36 minutes.
1 hr 36 min -----> 24 kg
96 min -----> 24000 grams
1 min -----> (24000/96) grams
1 min -----> 250 grams
So, David will prepare 200 grams of metal in one minute.
Problem 7 :
Mark used 15840 grams of metal to make an alloy in 45 minutes. Find the amount metal used in one minute (in grams).
Metal used in 45 minutes = 15840 grams
Metal used in 1 minute = (15840/45) grams
Metal used in 1 minute = 352 grams
So, 352 grams of metal is used in 1 minute.
Problem 8 :
Mrs. Moore handed out 40 grams of almonds to each of her 22 students . How many dekagrams of almonds did Mrs. Moore hand out ?
Total no. of grams of almonds handed out is
= 4 ⋅ 22
Here, we convert smaller unit (grams) into bigger unit (deagrams).
So we have to divide.
We now that,
1 dekagram = 10 grams
Then, the total no. of dekagrams of almonds handed out is
So, Mrs. Moore handed out 8.8 dekagrams of almonds.
Problem 9 :
Tommy uses 40 grams of cheese in each pizza he makes. How many kilograms of cheese does Tommy need to make 28 pizzas ?
Given : Tommy uses 40 grams of cheese in each pizza he makes.
1 pizza -----> 40 grams of cheese
28 pizzas -----> 28 ⋅ 40 grams of cheese
28 pizzas ------> 1120 grams of cheese
28 pizzas ------> (1120/1000) kilograms of cheese
28 pizzas ------> 1.12 kilograms
So, Tommy needs 1.12 kilograms of cheese to make 28 pizzas.
Problem 10 :
A standard elevator in a mid rise building can hold a maximum weight of about 500 kilograms. Assuming an average adult weight of 70 kilograms, what is the maximum number of adults who could safely ride the elevator ?
Given : Elevator can hold 500 kilograms.
If the average weight of an adult is 70 kilograms, then maximum no. of adults could safely ride the elevator is
So, maximum number of adults who could safely ride the elevator is 7.
After having gone through the problems explained above, we hope that the students would have understood how to solve word problems using conversions between different metric units.
Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.
You can also visit our following web pages on different stuff in math.
APTITUDE TESTS ONLINE
ACT MATH ONLINE TEST
TRANSFORMATIONS OF FUNCTIONS
ORDER OF OPERATIONS
Converting customary units worksheet
Customary units worksheet
Integers and absolute value worksheets
Nature of the roots of a quadratic equation worksheets
Trigonometry heights and distances
MATH FOR KIDS
Word problems on linear equations
Trigonometry word problems
Word problems on mixed fractrions
Converting repeating decimals in to fractions