CONTINUOUS COMPOUNDING FORMULA

Subscribe to our โ–ถ๏ธ YouTube channel ๐Ÿ”ด for the latest videos, updates, and tips.

In compound interest, we would have heard the terms like 'compounded annually', 'compounded semi annually', 'compounded quarterly' and 'compounded monthly'.

But, always we have question about compounded continuously. To understand 'compounded continuously', let us consider the example given below.

When we invest some money in a bank, it will grow continuously. That is, at any instant the balance is changing at a rate that equals 'r' (rate of interest per year) times the current balance.

Formula for compound interest :

A ---> Final value

P ---> Initial value

r ---> Growth rate (in percent)

t ---> Time (in years)

n ---> number of compounding periods



Annual compounding

1 time in a year

n = 1

Half yearly compounding

2 times in a year

n = 2

Quarterly compounding

4 times in a year

n = 4

Monthly compounding

12 times in a year

n = 12

Daily compounding

365 times in a year

n = 365

Continuous compounding

Infinite number of times in a year

n ---> โˆž

Many real world phenomena are being modeled by functions which describe how things grow continuously at any instance.

Suppose we want to compound continuously. This means that the number of compounding periods n grows without bound, i.e., n --->โˆž.

So, we have

When n ---> โˆž,

k ---> โˆžโ„แตฃ

k ---> โˆž

When n ---> โˆž, k ---> โˆž.

The formula given below is related to compound interest formula and represents the case where interest is being compounded continuously.

A = Pert

A ---> Final value

P ---> Initial value

r ---> Growth rate (in percent)

t ---> Time (in years)

Example 1 :

You invest $2500 in bank which pays 10% interest per year compounded continuously. What will be the value of the investment after 10 years ?

Solution :

Formula for continuous compounding :

A = Pert

Substitute P = 2500, r = 10% or 0.1, t = 10, e โ‰ˆ 2.71828.

A = 2500(2.71828)0.1 x 10

= 2500(2.71828)1

= $6795.70

Example 2 :

If David invests $500 at annual rate of 20% compounded continuously, calculate the final amount that David will have after 5 years.

Solution :

Formula for continuous compounding :

A = Pert

Substitute P = 500, r = 20% or 0.2, t = 5, e โ‰ˆ 2.71828.

A = 500(2.71828)0.2 x 5

= 500(2.71828)1

= $1359.14

Example 3 :

The zombie plague spreads exponentially at a rate of 10% per day, compounded continuously. If the zombie plague was contained in New York (about 0.28% of the world's population) but the containment was breached on February 4th, 2024. How many days until 95% of the world's population has contracted the zombie plague? Solve by logs, not by graphing.

Solution :

Formula for continuous compounding :

A = Pert

When the contracted was breached, 0.28% of the world's population has contracted the disease. That is, initially 0.28% of the world's population has contracted the the zombie plague.

P = 0.28% = 0.0028

A = 95% = 0.95

r = 10% = 0.1

Substitute A = 0.95, P = 0.0028 and r = 0.1 into the above formula.

0.95 = 0.0028e0.1t

Divide both sides by 0.0028.

339.2857...... = e0.1t

Take natural logarithm on both sides.

ln 339.2857...... = ln e0.1t

5.8268...... = (0.1t)ln e

5.8268...... = (0.1t)(1)

5.8268...... = 0.1t

Divide both sides by 0.1.

58.268...... = t

t = 58 days + part of the 59th day

t โ‰ˆ 59 days

95% of the world's population has contracted the zombie plague in about 59 days.

Subscribe to our โ–ถ๏ธ YouTube channel ๐Ÿ”ด for the latest videos, updates, and tips.

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

About Us  |  Contact Us  |  Privacy Policy

ยฉAll rights reserved. onlinemath4all.com

onlinemath4all_official_badge1.png

Recent Articles

  1. Digital SAT Math Problems and Solutions (Part - 1)

    Feb 05, 26 09:37 AM

    digitalsatmath1.png
    Digital SAT Math Problems and Solutions (Part - 1)

    Read More

  2. AP Precalculus Problems and Solutions

    Feb 05, 26 06:41 AM

    precalculus.png
    AP Precalculus Problems and Solutions

    Read More

  3. SAT Math Preparation with Hard Questions

    Feb 05, 26 05:30 AM

    SAT Math Preparation with Hard Questions

    Read More