CONSTANT RATES OF CHANGE WORKSHEET

Problem 1 : 

David drove for 3 hours at a rate of 50 miles per hour, for 2 hours at 60 miles per hour and for 4 hours at a rate of 70 miles per hour. What was his constant-speed for the whole journey?

Problem 2 : 

A person travels from New York to Washington at the rate of 45 miles per hour and comes backs to the New York at the rate of 55 miles per hour. What is his constant-speed for the whole journey? 

Problem 3 : 

A man takes 10 hours to go to a place and come back by walking both the ways. He could have gained 2 hours by riding both the ways. The distance covered in the whole journey is 18 miles. Find the constant speed for the whole journey if he goes by walking and comes back by riding.

Problem 4 : 

David travels from the place A to place B at a certain speed. When he comes back from place B to place A, he increases his speed 2 times. If the constant-speed for the whole journey is 80 miles per hour, find his speed when he travels from the place A to B.

Problem 5 : 

Kemka is preparing 20 cups of apple juice in the first 4 minutes and 60 cups in the next 12 minutes. How many cups does she prepare per minute?

Answers

1. Answer :

Step 1 :

Formula for constant speed :

=  Total distance/Total time taken

Formula for distance :

=  Rate x Time

Step 2 :

Distance covered in the first 3 hours : 

=  50 x 3

=  150 miles

Distance covered in the next 2 hours :

=  60 x 2

=  120 miles

Distance covered in the last 4 hours

=  70 x 5

=  350 miles

Step 3 :

Then,

total distance  =  150 + 120 + 350  =  620 miles

total time  =  3 + 2 + 5  = 10 hours 

Step 4 :

So, constant speed is

=  Total distance/Total time taken

=  620/10

=  62 miles per hour

2. Answer :

Step 1 :

Here, both the ways, he covers the same distance.

Then, formula for constant speed  =  2xy/(x + y)

Step 2 :

x ----> Rate at which he travels from New York to Washington. 

x  =  45

y ----> Rate at which he travels from New York to Washington 

y  =  55

Step 3 :

So, constant speed is

=  2(45)(55)/(45 + 55)

=  4950/100

=  49.5 miles per hour

3. Answer :

Step 1 :

Walking + Walking  =  10 hours -----> walking  =  5 hours

Riding + Riding  =  8  hours    (Because 2 hours gained)

Then, Riding  =  4 hours

Walking + Riding -----> ( 5 + 4 )  =  9 hours

Step 2 :

Total time taken  =  9 hours

Total distance covered  =  18 miles 

Step 3 :

So, constant speed is 

=  Total distance/Total time taken

=  18/9

=  2 miles per hour

4. Answer :

Step 1 :

Let 'a' be the speed from place A to B.

Then, speed from place B to A  =  2a

Step 2 :

Here, both the ways, he covers the same distance.

Then, formula for constant speed  =  2xy/(x + y)

Step 3 :

x ----> Speed from place A to B

x  =  a

y ----> Speed from place B to A

y  =  2a

Step 4 :

Given : Constant speed  =  80 miles/hour

2(a)(2a)/(a + 2a)  =  80

4a2/3a  =  80

4a/3  =  80

a  =  60

Speed from place A to B is 60 miles per hour.

5. Answer :

Step 1 :

Total no. of cups of apple juice prepared  is

=  20 + 60

=  80 cups

Step 2 :

Total time taken is

=  4 + 12

=  16 minutes

Step 3 :

Number of cups of apple juice prepared per minute is 

=  Total number of cups/Total time taken

=  80/16

= 5 

Kemka prepares 5 cups of apple juice per minutes.

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. First Fundamental Theorem of Calculus - Part 1

    Apr 17, 24 11:27 PM

    First Fundamental Theorem of Calculus - Part 1

    Read More

  2. Polar Form of a Complex Number

    Apr 16, 24 09:28 AM

    polarform1.png
    Polar Form of a Complex Number

    Read More

  3. Conjugate of a Complex Number

    Apr 15, 24 11:17 PM

    conjugateofcomplexnumber1.png
    Conjugate of a Complex Number

    Read More