COMPARING RATIONAL NUMBERS

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A rational number is a number which is in the form of ᡃ⁄b where a and b are integers and b β‰  0.

Let us learn how to compare two rational numbers.

Comparing Two Positive Rational Numbers with Same Denominator

If two rational numbers are positive with same denominator, compare the numerators and decide the larger and smaller.

For example, consider the two rational numbers ³⁄₇ and ⁡⁄₇.

Both the rational numbers are positive and they have the same denominator 7.

Compare the numerators 3 and 5.

3 < 5

Therefore,

³⁄₇ < β΅β„₇

Comparing Two Negative Rational Numbers with Same Denominator

If two rational numbers are negative with same denominator, compare the numerators and decide the larger and smaller.

For example, consider the two rational numbers ⁻³⁄₇ and ⁻⁡⁄₇.

Both the rational numbers are negative and they have the same denominator 7.

Compare the numerators -3 and -5.

-3 > -5

Therefore,

⁻³⁄₇ > β»β΅β„₇

Comparing Two Rational Numbers with Different Signs

In two rational numbers, if one is positive and other one is negative, then it is pretty easy to compare those two rational numbers. The positive rational number is greater than the negative rational number.

For example, consider the two rational numbers ⁻²⁄₅ and β…›.

Clearly, the positive rational number β…› is greater than the negative rational number β»Β²β„β‚….

⁻²⁄₅ β…›

Comparing Two Rational with Same Sign and Different Denominators

The following steps will be useful to compare two rational numbers with same sign and different denominators.

Step 1 :

Find the least common multiple of the two different denominators.

Step 2 :

Make the least commom multiple found in step 1 as denominator for each fraction by multiplying the fractions by appropriate numbers.

Step 3 :

Now, compare the numerators and decide the larger and smaller.

For example, consider the two rational numbers ΒΎ and β…š.

The least common multiple of the denominators 4 and 6 is 12.

Multiply both numerator and denominator of the fraction ΒΎ by 3 to get the denominator 12.

β½Β³Λ£Β³βΎβ„β‚β‚„β‚“β‚ƒβ‚Ž = βΉβ„₁₂ ----(1)

Multiply both numerator and denominator of the fraction β…š by 2 to get the denominator 12.

β½β΅Λ£Β²βΎβ„β‚β‚†β‚“β‚‚β‚Ž = ΒΉβ°β„₁₂ ----(2)

In (1) and (2), compare the numerators 9 and 10.

9 < 10

Therefore,

⁹⁄₁₂ ΒΉβ°β„₁₂ ----> ΒΎ β…š

Solved Examples

In each of the following examples, compare the two rational numbers :

Example 1 :

β…— and β…–

Solution :

Both β…— and β…– are positive with same denominator.

Compare the numerators 3 and 2.

3 > 2

Therefore,

β…— > β…–

Example 2 :

⁻⁡⁄₇ and β»β΄β„₇

Solution :

Both ⁻⁡⁄₇ and β»β΄β„₇ are negative with same denominator.

Compare the numerators -5 and -4.

-5 < -4

Therefore,

⁻⁡⁄₇ β»β΄β„₇

Example 3 :

⁻²⁄₅ and β…•

Solution :

Since ⁻²⁄₅ and β…• are having different signs, the positive rational number is always greater than the negative rational number.

Therefore,

⁻²⁄₅ β…•

Example 4 :

β…™ and ΒΌ

Solution :

Since β…™ and ΒΌ are having different denominators, find the least common multiple of the denominators.

Least common multiple of (6, 4) = 12.

Make 12 as denominator for both the fractions by multiplying both the fractions by the approproate numbers. 

Multiply both numerator and denominator of the fraction β…™ by 2 to get the denominator 12.

β½ΒΉΛ£Β²βΎβ„β‚β‚†β‚“β‚‚β‚Ž = Β²β„₁₂ ----(1)

Multiply both numerator and denominator of the fraction ΒΌ by 3 to get the denominator 12.

β½ΒΉΛ£Β³βΎβ„β‚β‚„β‚“β‚ƒβ‚Ž = Β³β„₁₂ ----(2)

In (1) and (2), compare the numerators.

2 < 3

Therefore,

²⁄₁₂ Β³β„₁₂ ----> β…™ ΒΌ

Example 5 :

⁻¹¹⁄₅ and β»Β²ΒΉβ„β‚ˆ

Solution :

Since ⁻¹¹⁄₅ and β»Β²ΒΉβ„β‚ˆ are having different denominators, find the least common multiple of the denominators.

Least common multiple of (5, 8) = 40.

Make 40 as denominator for both the fractions by multiplying both the fractions by the approproate numbers. 

Multiply both numerator and denominator of the fraction ⁻¹¹⁄₅ by 8 to get the denominator 40.

β½β»ΒΉΒΉΛ£βΈβΎβ„β‚β‚…β‚“β‚ˆβ‚Ž = β»βΈβΈβ„β‚„β‚€ ----(1)

Multiply both numerator and denominator of the fraction β»Β²ΒΉβ„β‚ˆ by 5 to get the denominator 40.

β½β»Β²ΒΉΛ£β΅βΎβ„β‚β‚ˆβ‚“β‚…β‚Ž = β»ΒΉβ°β΅β„β‚„β‚€ ----(2)

In (1) and (2), compare the numerators.

-88 > -105

Therefore,

⁻⁸⁸⁄₄₀ β»ΒΉβ°β΅β„β‚„β‚€ ----> ⁻¹¹⁄₅ β»Β²ΒΉβ„β‚ˆ

Example 6 :

³⁄₋₄ and β»ΒΉβ„β‚‚

Solution :

³⁄₋₄ can be written as ⁻³⁄₄.

Since ⁻³⁄₄ and β»ΒΉβ„β‚‚ are having different denominators, find the least common multiple of the denominators.

Least common multiple of (4, 2) = 4.

The fraction ⁻³⁄₄ is already having the denominator 4.

⁻³⁄₄ ----(1)

Multiply both numerator and denominator of the fraction ⁻¹⁄₂ by 2 to get the denominator 4.

β½β»ΒΉΛ£Β²βΎβ„β‚β‚‚β‚“β‚‚β‚Ž = β»Β²β„β‚„ ----(2)

In (1) and (2), compare the numerators.

-3 < -2

Therefore,

⁻³⁄₄ β»Β²β„β‚„ ----> ³⁄₋₄ < β»ΒΉβ„β‚‚

Example 7 :

β…˜ and β…”

Solution :

Since β…˜ and β…” are having different denominators, find the least common multiple of the denominators.

Least common multiple of (5, 3) = 15.

Make 15 as denominator for both the fractions by multiplying both the fractions by the approproate numbers.

Multiply both numerator and denominator of the fraction β…˜ by 3 to get the denominator 15.

β½β΄Λ£Β³βΎβ„β‚β‚…β‚“β‚ƒβ‚Ž = ΒΉΒ²β„₁₅ ----(1)

Multiply both numerator and denominator of the fraction β…” by 5 to get the denominator 15.

β½Β²Λ£β΅βΎβ„β‚β‚ƒβ‚“β‚…β‚Ž = ΒΉβ°β„₁₅ ----(2)

In (1) and (2), compare the numerators.

12 > 10

Therefore,

¹²⁄₁₅ ΒΉβ°β„₁₅ ----> β…˜ β…”

Example 8 :

β»Β³β„β‚ˆ and β»Β²β„β‚‹β‚…

Solution :

⁻²⁄₋₅ Β²β„β‚…

Since β»Β³β„β‚ˆ and Β²β„β‚… are having different signs, the positive rational number is always greater than the negative rational number.

Therefore,

β»Β³β„β‚ˆ Β²β„β‚… ----> β»Β³β„β‚ˆ β»Β²β„β‚‹β‚…

Arranging the Rational Numbers in Ascending Order and Descending Order

In each of the following examples, compare the given rational numbers and arrange them in ascending and descending orders.

Example 9 :

⁻⁡⁄₁₂, β»ΒΉΒΉβ„β‚ˆ, β»ΒΉβ΅β„β‚‚β‚„, β»β·β„₋₉, ΒΉΒ²β„₃₆

Solution :

Least common multiple of (12, 8, 24, 9, 36) = 144.

β½β»β΅Λ£ΒΉΒ²βΎβ„β‚β‚β‚‚β‚“β‚β‚‚β‚Ž = β»βΆβ°β„₁₄₄

β½β»ΒΉΒΉΛ£ΒΉβΈβΎβ„β‚β‚ˆβ‚“β‚β‚ˆβ‚Ž = β»ΒΉβΉβΈβ„₁₄₄

β½β»ΒΉβ΅Λ£βΆβΎβ„β‚β‚‚β‚„β‚“β‚†β‚Ž = β»βΉβ°β„₁₄₄

β½β»β·Λ£ΒΉβΆβΎβ„β‚β‚‹β‚‰β‚“β‚β‚†β‚Ž = ΒΉΒΉΒ²β„₁₄₄

β½ΒΉΒ²Λ£β΄βΎβ„β‚β‚ƒβ‚†β‚“β‚„β‚Ž = β΄βΈβ„₁₄₄

⁻¹⁹⁸⁄₁₄₄ > ⁻⁹⁰⁄₁₄₄ > ⁻⁢⁰⁄₁₄₄ > ⁴⁸⁄₁₄₄ > ¹¹²⁄₁₄₄

Ascending Order :

β»ΒΉΒΉβ„β‚ˆβ»ΒΉβ΅β„β‚‚β‚„β»β΅β„β‚β‚‚, ΒΉΒ²β„₃₆, β»β·β„₋₉

Descending Order :

β»β·β„β‚‹β‚‰ΒΉΒ²β„β‚ƒβ‚†β»β΅β„β‚β‚‚β»ΒΉβ΅β„β‚‚β‚„β»ΒΉΒΉβ„β‚ˆ

Example 10 :

⁻¹⁷⁄₁₀, β»β·β„β‚…, 0, ⁻²⁄₄, β»ΒΉβΉβ„β‚‚β‚€

Solution :

Least common multiple of (10, 5, 4, 20) = 20.

β½β»ΒΉβ·Λ£Β²βΎβ„β‚β‚β‚€β‚“β‚‚β‚Ž = β»Β³β΄β„β‚‚β‚€

β½β»β·Λ£β΄βΎβ„β‚β‚…β‚“β‚„β‚Ž = β»Β²βΈβ„β‚‚β‚€

β½β»Β²Λ£β΅βΎβ„β‚β‚„β‚“β‚…β‚Ž = β»ΒΉβ°β„β‚‚β‚€

β½β»ΒΉβΉΛ£ΒΉβΎβ„β‚β‚‚β‚€β‚“β‚β‚Ž = β»ΒΉβΉβ„β‚‚β‚€

⁻³⁴⁄₂₀ > ⁻²⁸⁄₂₀⁻¹⁹⁄₂₀ > ⁻¹⁰⁄₂₀ > 0

Ascending Order :

⁻¹⁷⁄₁₀, β»β·β„β‚…, β»ΒΉβΉβ„β‚‚β‚€, ⁻²⁄₄, 0

Descending Order :

0, ⁻²⁄₄, ⁻¹⁹⁄₂₀, ⁻⁷⁄₅, ⁻¹⁷⁄₁₀

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