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Questions 1-12 : Compare the given two rational numbers.
Question 1 :
Β³ββ and β΅ββ
Question 2 :
β and β
Question 3 :
β»Β³ββ and β»β΅ββ
Question 4 :
β»β΅ββ and β»β΄ββ
Question 5 :
β»Β²ββ and β
Question 6 :
Β²ββ and β»β
Question 7 :
β and ΒΌ
Question 8 :
ΒΎ and β
Question 9 :
β»ΒΉΒΉββ and β»Β²ΒΉββ
Question 10 :
Β³βββ and β»ΒΉββ
Question 11 :
β and β
Question 12 :
β»Β³ββ and β»Β²βββ
Questions 13-14 : Compare the given rational numbers and arrange them in ascending and descending orders.
Question 13 :
β»β΅βββ, β»ΒΉΒΉββ, β»ΒΉβ΅βββ, β»β·βββ, ΒΉΒ²βββ
Question 14 :
β»ΒΉβ·βββ, β»β·ββ , 0, β»Β²ββ, β»ΒΉβΉβββ

1. Answer :
Both Β³ββ and β΅ββ are positive and they have the same denominator 7.
Compare the numerators 3 and 5.
3 < 5
Therefore,
Β³ββ < β΅ββ
2. Answer :
Both β and β are positive with same denominator.
Compare the numerators 3 and 2.
3 > 2
Therefore,
β > β
3. Answer :
Both β»Β³ββ and β»β΅ββ are negative with same denominator.
Compare the numerators -3 and -5.
-3 > -5
Therefore,
β»Β³ββ > β»β΅ββ
4. Answer :
Both β»β΅ββ and β»β΄ββ are negative with same denominator.
Compare the numerators -5 and -4.
-5 < -4
Therefore,
β»β΅ββ < β»β΄ββ
5. Answer :
Since β»Β²ββ and β are having different signs, the positive rational number is always greater than the negative rational number.
Therefore,
β»Β²ββ < β
6. Answer :
Since Β²ββ and β»β are having different signs, the positive rational number is always greater than the negative rational number.
Therefore,
Β²ββ > β»β
7. Answer :
Since β and ΒΌ are having different denominators, find the least common multiple of the denominators.
Least common multiple of (6, 4) = 12.
Make 12 as denominator for both the fractions by multiplying both the fractions by the approproate numbers.
Multiply both numerator and denominator of the fraction β
by 2 to get the denominator 12.
β½ΒΉΛ£Β²βΎββββββ = Β²βββ ----(1)
Multiply both numerator and denominator of the fraction ΒΌ by 3 to get the denominator 12.
β½ΒΉΛ£Β³βΎββββββ = Β³βββ ----(2)
In (1) and (2), compare the numerators.
2 < 3
Therefore,
Β²βββ < Β³βββ ----> β < ΒΌ
8. Answer :
Since ΒΎ and β are having different denominators, find the least common multiple of the denominators.
Least common multiple of (4, 6) = 12.
Make 12 as denominator for both the fractions by multiplying both the fractions by the approproate numbers.
Multiply both numerator and denominator of the fraction ΒΎ by 3 to get the denominator 12.
β½Β³Λ£Β³βΎββββββ = βΉβββ ----(1)
Multiply both numerator and denominator of the fraction β by 2 to get the denominator 12.
β½β΅Λ£Β²βΎββββββ = ΒΉβ°βββ ----(2)
In (1) and (2), compare the numerators 9 and 10.
9 < 10
Therefore,
βΉβββ < ΒΉβ°βββ ----> ΒΎ < β
9. Answer :
Since β»ΒΉΒΉββ and β»Β²ΒΉββ are having different denominators, find the least common multiple of the denominators.
Least common multiple of (5, 8) = 40.
Make 40 as denominator for both the fractions by multiplying both the fractions by the approproate numbers.
Multiply both numerator and denominator of the fraction β»ΒΉΒΉββ
by 8 to get the denominator 40.
β½β»ΒΉΒΉΛ£βΈβΎβββ βββ = β»βΈβΈβββ ----(1)
Multiply both numerator and denominator of the fraction β»Β²ΒΉββ by 5 to get the denominator 40.
β½β»Β²ΒΉΛ£β΅βΎβββββ β = β»ΒΉβ°β΅βββ ----(2)
In (1) and (2), compare the numerators.
-88 > -105
Therefore,
β»βΈβΈβββ > β»ΒΉβ°β΅βββ ----> β»ΒΉΒΉββ > β»Β²ΒΉββ
10. Answer :
Β³βββ can be written as β»Β³ββ.
Since β»Β³ββ and β»ΒΉββ are having different denominators, find the least common multiple of the denominators.
Least common multiple of (4, 2) = 4.
The fraction β»Β³ββ is already having the denominator 4.
β»Β³ββ ----(1)
Multiply both numerator and denominator of the fraction β»ΒΉββ by 2 to get the denominator 4.
β½β»ΒΉΛ£Β²βΎββββββ = β»Β²ββ ----(2)
In (1) and (2), compare the numerators.
-3 < -2
Therefore,
β»Β³ββ < β»Β²ββ ----> Β³βββ < β»ΒΉββ
11. Answer :
Since β and β are having different denominators, find the least common multiple of the denominators.
Least common multiple of (5, 3) = 15.
Make 15 as denominator for both the fractions by multiplying both the fractions by the approproate numbers.
Multiply both numerator and denominator of the fraction β by 3 to get the denominator 15.
β½β΄Λ£Β³βΎβββ βββ = ΒΉΒ²βββ ----(1)
Multiply both numerator and denominator of the fraction β
by 5 to get the denominator 15.
β½Β²Λ£β΅βΎβββββ β = ΒΉβ°βββ ----(2)
In (1) and (2), compare the numerators.
12 > 10
Therefore,
ΒΉΒ²βββ > ΒΉβ°βββ ----> β > β
12. Answer :
β»Β²βββ
= Β²ββ
Since β»Β³ββ and Β²ββ are having different signs, the positive rational number is always greater than the negative rational number.
Therefore,
β»Β³ββ < Β²ββ ----> β»Β³ββ < β»Β²βββ
13. Answer :
β»β΅βββ, β»ΒΉΒΉββ, β»ΒΉβ΅βββ, β»β·βββ, ΒΉΒ²βββ
Least common multiple of (12, 8, 24, 9, 36) = 144.
β½β»β΅Λ£ΒΉΒ²βΎββββββββ = β»βΆβ°ββββ
β½β»ΒΉΒΉΛ£ΒΉβΈβΎβββββββ = β»ΒΉβΉβΈββββ
β½β»ΒΉβ΅Λ£βΆβΎβββββββ = β»βΉβ°ββββ
β½β»β·Λ£ΒΉβΆβΎββββββββ = ΒΉΒΉΒ²ββββ
β½ΒΉΒ²Λ£β΄βΎβββββββ = β΄βΈββββ
β»ΒΉβΉβΈββββ > β»βΉβ°ββββ > β»βΆβ°ββββ > β΄βΈββββ > ΒΉΒΉΒ²ββββ
Ascending Order :
β»ΒΉΒΉββ, β»ΒΉβ΅βββ, β»β΅βββ, ΒΉΒ²βββ, β»β·βββ
Descending Order :
β»β·βββ, ΒΉΒ²βββ, β»β΅βββ, β»ΒΉβ΅βββ, β»ΒΉΒΉββ
14. Answer :
β»ΒΉβ·βββ, β»β·ββ , 0, β»Β²ββ, β»ΒΉβΉβββ
Least common multiple of (10, 5, 4, 20) = 20.
β½β»ΒΉβ·Λ£Β²βΎβββββββ = β»Β³β΄βββ
β½β»β·Λ£β΄βΎβββ βββ = β»Β²βΈβββ
β½β»Β²Λ£β΅βΎβββββ β = β»ΒΉβ°βββ
β½β»ΒΉβΉΛ£ΒΉβΎβββββββ = β»ΒΉβΉβββ
β»Β³β΄βββ > β»Β²βΈβββ > β»ΒΉβΉβββ > β»ΒΉβ°βββ > 0
Ascending Order :
β»ΒΉβ·βββ, β»β·ββ , β»ΒΉβΉβββ, β»Β²ββ, 0
Descending Order :
0, β»Β²ββ, β»ΒΉβΉβββ, β»β·ββ , β»ΒΉβ·βββ
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