## Combination of Solids Solution9

In this page combination of solids solution9 we are going to see solution some practice questions of the worksheet combination of solid worksheet2.

Question 9:

Though a cylindrical pipe of internal radius 7 cm, water flows out at the rate of 5 cm/sec. Calculate the volume of water (in liters) discharged through the pipe in half an hour.

Solution: Now we need to find volume of water (in liters) discharged through the pipe in half an hour. For that let us convert speed into seconds.

half an hour = 30 minutes

let us change minutes into seconds. For that we have to multiply 30 by 60. Because 60 seconds = 1 minute.

30 x 60 = 1800 seconds.

Volume of water discharged in

half an hour       = Area of cross section x time x speed

= Π r² x 5 x 1800

= (22/7) (7)² x 5 x 1800

= (22/7) x (7) x (7) x 5 x 1800

= 22 x 7 x 5 x 1800

= 1386000 cubic cm

But here we have to find volume of water discharged in liters. For that we have to use the following conversion that is

1000 cm³ = 1 liter

= 1386000/1000

= 1386 liter combination of solids solution9 combination of solids solution9 