CHOOSING A FACTORING METHOD WORKSHEET

Problem 1 :

x2 + 2x + xy + 2y

Problem 2 :

2ax2 + bx2 - 2ay2 - by2

Problem 3 :

x3 + x2 - x - 1

Problem 4 :

2x2 - 8

Problem 5 :

2x - 2xy2

Problem 6 :

3t3 - 27t

Problem 7 :

4x4 - 4x2

Problem 8 :

3x + x2 - 10

Problem 9 :

x+ 8x2 - x - 8

Problem 10 :

4a3 - 49a

Problem 11 :

2y2 - 16y + 32

Problem 12 :

p2 q - 25q + 3q2 - 75

Problem 13 :

16 - w4

Problem 14 :

64x3 + 27

Problem 15 :

3t3 - 27t

Detailed Answer Key


Problem 1 :

x2 + 2x + xy + 2y

Solution :

x2 + 2x + xy + 2y

Since we have four terms in the given expression, we have to use the method of grouping and do the factoring.

Factoring x from first two terms and factoring y from third and fourth terms.

= x (x + 2) + y (x + 2)

= (x + y)(x + 2)

So, the factored form of the given expression is 

(x + y)(x + 2)

Problem 2 :

2ax2 + bx2 - 2ay2 - by2

Solution :

2ax2 + bx2 - 2ay2 - by2

Since we have four terms in the given expression, we have to use grouping method.

Factoring x2 from first and second term, factoring y2 from third and fourth term.

x2 (2a + b) - y2 (2a + b)

= (x2 - y2) (2a + b) 

So, the factored form of the given expressions is

(x2 - y2) (2a + b)

Problem 3 :

x3 + x2 - x - 1

Solution :

x3 + x2 - x - 1

Since we have four terms in the given expression, we have to use grouping method.

Factoring x2 from first and second term, factoring -1 from third and fourth terms.

x2 (x + 1) - 1(x + 1)

= (x2  - 1)(x + 1)

Here (x2  - 1) looks like a2 - b2, by expanding this using algebraic identity, we get (a + b) (a - b)

= (x + 1)(x - 1)(x + 1)

Since x + 1 is repeating twice, we write in the exponential form

= (x + 1)2(x - 1)

Problem 4 :

2x2 - 8

Solution :

= 2x2 - 8

= 2(x2 - 4)

= 2(x2 - 22)

= 2(x + 2)(x - 2)

So, the factored form of the expression is 2(x + 2)(x - 2).

Problem 5 :

2x - 2xy2

Solution :

= 2x - 2xy2

Factoring 2x, we get

= 2x (1 - y2)

Here 1 - y2, looks like a2 - b2 then (a + b) (a - b)

= 2x(1 + y)(1 - y)

Problem 6 :

3t3 - 27t

Solution :

= 3t3 - 27t

Factoring 3t, we get

= 3t(t2 - 9)

= 3t(t2 - 32)

Here t2 - 32, looks like a2 - b2 then (a + b) (a - b)

= 3t (t + 3)(t - 3)

So, the factored form of the given expression is 

3t (t + 3)(t - 3)

Problem 7 :

4x4 - 4x2

Solution :

Factoring 4x2 from these two terms

= 4x2 (x2  - 1)

Here x2 - 12, looks like a2 - b2 then (x + 1)(x - 1)

= 4x2 (x + 1)(x - 1)

Problem 8 :

3x + x2 - 10

Solution :

3x + x2 - 10

It is a trinomial, but it is not in the standard form.

= x2 + 3x - 10

By splitting the middle term, we get

= x2 + 5x - 2x - 10

= x(x + 5) - 2(x + 5)

= (x - 2)(x + 5)

So, the factored form of the given expression is 

(x - 2)(x + 5)

Problem 9 :

x+ 8x2 - x - 8

Solution :

= x+ 8x2 - x - 8

= x2(x + 8) - 1(x + 8)

= (x2 - 1)(x + 8)

= (x + 1)(x - 1)(x + 8)

So, the factored form of the given expression is 

(x + 1)(x - 1)(x + 8)

Problem 10 :

4a3 - 49a

Solution :

4a3 - 49a

Factoring a from the given expression.

= a(4a2 - 49)

= a((2a)2 - 72)

= a(2a + 7)(2a - 7)

So, the factored form of the given expression is

a(2a + 7)(2a - 7)

Problem 11 :

2y2 - 16y + 32

Solution :

= 2y2 - 16y + 32

Factoring 2, we get

= 2(y2 - 8y + 16)

= 2(y2 - 4y - 4y + 16)

= 2[y(y - 4) - 4(y - 4)]

= 2(y - 4)(y - 4)

So, the factored form of the given expression is 

 2(y - 4)(y - 4)

Problem 12 :

p2 q - 25q + 3q2 - 75

Solution :

= p2 q - 25q + 3q2 - 75

= q(p2 - 25) + 3(p2 - 25)

= (q + 3)(p2 - 25)

Here (p2 - 25) looks like a- b2, expanding this using algebraic identity, we get

= (q + 3)(q + 5)(q - 5)

Problem 13 :

16 - w4

Solution :

= 16 - w4

= 42 - (w2)2

= (4 + w2) (4 - w2)

= (4 + w2) (22 - w2)

= (4 + w2) (2 + w)(2 - w)

So, the factored form of the given expression is 

(4 + w2) (2 + w)(2 - w)

Problem 14 :

64x3 + 27

Solution :

= 64x3 + 27

= (4x)3 + 33

Looks like a3 + b3 = (a + b) (a2 - ab + b2)

= (4x + 3)((4x)2 - 4x(3) + 32)

= (4x + 3)(16x2 - 12x + 9)

Problem 15 :

3t3 - 27t

Solution :

3t3 - 27t

= 3t(t2 - 9)

= 3t(t2 - 32)

= 3t(t + 3)(t - 3)

So, the factored form of the expression is 

3t(t + 3)(t - 3)

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