# CHECK WHETHER THE GIVEN STATEMENT WILL BE ARITHMETIC PROGRESSION

Check Whether the Given Statement Will be Arithmetic Progression :

Here we are going to see some examples problem to show how we decide the given statement is arithmetic progression or not.

## Check Whether the Given Statement Will be Arithmetic Progression - Exmaples

Question 1 :

In which of the following situations ,does the list of numbers involved make an arithmetic progression,and why?

(i) The taxi fare each km when the fare is Rs.15 for the first km and Rs.8 for each additional km.

Solution :

From the above given information we come to know that,

Taxi fare for 1st km = 15

Taxi fare for 2nd km = 15 + 8 = 23

Taxi fare for 3rd km = 23 + 8 = 31

15, 23, 31,.................

Every term of this sequence is 8 more than the previous term. This sequence clearly form an A.P

(ii) The amount of air present in a cylinder when a vacuum pump removes 1/4 of the air remaining in the cylinder at a time.

Solution :

Let "x" be the amount of air present in a cylinder

In each stroke vacuum pump removes 1/4 of the air remaining in the cylinder at a time.

In other words, after every stroke, only 1-(1/4) = (3/4)th part of air will remain.

The volumes will be x,(3x/4),(3x/4)²,,,,,,,,,

Since the common difference are not same, the given sequence will be arithmetic progression.

(iii) The cost of digging a well after every meter of digging,when it costs Rs.150 for first meter and rises by Rs.50 for each subsequent meters.

Solution :

Cost of digging for the first meter  =  Rs.150

Cos t of digging for the second meter  =  150 + 50

=  Rs. 200

Cost of digging for the third meter = 200 + 50

=  Rs. 250

150, 200, 250,..............

Every term is 50 more than the previous term, since the common difference is same. It is A.P

(iv) The amount of money in the account every year,when Rs.10000 is deposited at compound interest at 8% per annum.

Solution :

We know that if Rs P is deposited at r% compound interest per annum for n years, our money will be p[1+(r/100)]^n after n years.

Therefore, after every year, our money will be

10000(1.08),10000(1.08)²,10000(1.08)³,..............

Since the common difference is not same. The given statement is not Arithmetic progression.

After having gone through the stuff given above, we hope that the students would have understood, check whether the given statement will be arithmetic progression.

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