Characteristics of quadratic functions :
If we draw a graph for a quadratic equation we will get the shape parabola. Each quadratic functions will have some characters.
Axis of symmetry :
The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.
x and y intercepts :
The point at which the parabola cuts the x-axis is known as x-intercept.To find x-intercept we have to put y = 0.
The point at which the parabola cuts the y-axis is known as y-intercept.To find y-intercept we have to put x = 0.
We can get the zeroes of a quadratic function by applying y = 0. Zeroes of a quadratic function and x-intercepts are same.
The vertex of a parabola is the point where the parabola crosses its axis of symmetry.
The vertex of the parabola is the highest or lowest point also known as maximum value or minimum value of the parabola.
point symmetric to y-intercept :
The y-intercept (and other points) can be reflected across the axis of symmetry to find other points on the graph of the function.
The points which are having same horizontal distance from the axis is known as symmetric points.
Symmetric points is also known as mirror point.
Example 1 :
Find the equation of axis of symmetry, x and y intercepts, zeroes, vertex and point symmetric to y-intercept. Sketch the graph of the equation.
y = x² - 2 x - 1
y = x² - 2 x - 1
y = ax² + bx + c
a = 1, b = -2 and c = -1
The given parabola is symmetric about y axis. Since a > 0 the parabola is open upward.
Equation of axis :
x = -b/2a
x = -(-2)/2(-1) ==> 1
Equation of axis is y = 1
X and y -intercepts :
put y = 0
0 = x² - 2 x - 1
(x - 2) (x + 1) = 0
x = -1,2
x intercepts are -1 and 2
put x = 0
y = 0² - 2(0) - 1
y = -1
y-intercept is -1
Let p(x) = x² - 2 x - 1
p(x) = 0
x² - 2 x - 1 = 0
solving the given quadratic equation using quadratic formula we get
x = 2 ± √4 - 4(1)(-1)/2(1)
x = (2 ± √8)/2
x = 1 ± √2
x = 1 + √2, x = 1 - √2
x = 2.414, -0.414
Vertex of parabola is (h, k). Here h = -b/2a
x = -b/2a, x = 1
plug x = 1 in the given equation in order to get the value of y.
y = 1² - 2(1) - 1 ==> y = 1 - 3 ==> y = -2
Vertex of the parabola is (1, -2)
Point symmetric to y-intercept :
The point symmetric to y intercept will have the same horizontal distance from the axis of symmetry.
To find that point we have to apply the value of y in the given equation.
y = -1
x² - 2 x - 1 = -1
x² - 2 x = 0
x (x - 2) = 0
x = 0 and x = 2
Hence point symmetric to y-intercept is (2, -1)
After having gone through the stuff given above, we hope that the students would have understood "Characteristics of quadratic functions".
Apart from the stuff given above, if you want to know more about "Characteristics of quadratic functions", please click here
Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.
APTITUDE TESTS ONLINE
ACT MATH ONLINE TEST
TRANSFORMATIONS OF FUNCTIONS
ORDER OF OPERATIONS
Decimal place value worksheets
Area and perimeter
Different forms equations of straight lines
MATH FOR KIDS
HCF and LCM word problems
Word problems on quadratic equations
Word problems on comparing rates
Ratio and proportion word problems
Converting repeating decimals in to fractions