In this page characteristic roots question1 we are going to see how to find characteristic roots of any given matrix.
Definition :
Let A be any square matrix of order n x n and I be a unit matrix of same order. Then |A-λI| is called characteristic polynomial of matrix.
Then the equation |A-λI| = 0 is called characteristic roots of matrix. The roots of this equation is called characteristic roots of matrix.
Another name of characteristic roots:
characteristic roots are also known as latent roots or eigenvalues of a matrix.
Question 1 :
Determine the characteristic roots of the matrix
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Solution:
Let A = |
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The order of A is 3 x 3. So the unit matrix I = |
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Now we have to multiply λ with unit matrix I.
λI = |
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A-λI= |
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= (5-λ)[(-2-λ) (5-λ) - 0] - 0 [(0 - 0)] + 1 [0- (-2 -λ)] = (5-λ)[ -10 + 2 λ - 5 λ + λ²] - 0 + 2 + λ = (5-λ)[ -10 - 3 λ + λ²] - 0 + 2 + λ = (5-λ)[λ² -3 λ-10] + 2 + λ = 5 λ² - 15 λ - 50 - λ³ + 3 λ² + 10 λ + 2 + λ = - λ³ + 5 λ² + 3 λ² - 15 λ + 10 λ + λ - 50 + 2 = - λ³ + 8 λ² - 4 λ - 48 = λ³ - 8 λ² + 4 λ + 48 |
To find roots let |A-λI| = 0
λ³ - 8 λ² + 4 λ + 48 = 0
For solving this equation first let us do synthetic division.characteristic roots question1
By using synthetic division we have found one value of λ that is λ = -2.
Now we have to solve λ² - 10 λ + 24 to get another two values. For that let us factorize
λ² - 10 λ + 24 = 0
λ² - 6 λ - 4 λ + 24 = 0
λ (λ - 6) - 4 (λ - 6) = 0
(λ - 6) (λ - 4) = 0
λ - 6 = 0
λ = 6
λ - 4 = 0
λ = 4
Therefore the characteristic roots (or) Eigen values are x = -2,4,6
Questions |
Solution |
Question 2 : Determine the characteristic roots of the matrix
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Question 3 : Determine the characteristic roots of the matrix
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Question 4 : Determine the characteristic roots of the matrix
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Question 5 : Determine the characteristic roots of the matrix characteristic roots question 1 characteristic roots question 1
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characteristic roots question 1 characteristic roots question 1 |
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