# ARITHMETIC PRACTICE PROBLEMS WITH SOLUTIONS

## About "Arithmetic Practice Problems With Solutions"

Arithmetic Practice Problems With Solutions :

Here we are going to see some practice questions of the math topic "Arithmetic".

To find question from 1 to 6, please visit the page "SHSAT Arithmetic Practice".

To find question from 7 to 10, please visit the page "SHSAT Arithmetic Practice Problems".

## SHSAT Arithmetic Practice Problems - Practice questions

Question 11 :

If u-4  =  16, what is one possible value of u ?

(A)  4   (B)  2  (C)  1  (D)  1/2  (E)  1/4

Solution :

u-4  =  16

u-4  =  24

u4  =  1/24

u = 1/2

Hence the value of u is 1/2.

Question 12 :

If a kilogram is equal to approximately 2.2 pounds, which of the following is the best approximation of the number of kilograms in one pound ?

(A)  11/5  (B)  5/8  (C)  5/11  (D)  1/3  (E)  1/5

Solution :

To get rid of decimals in a fraction, multiply the top and bottom by the smaller power of 10 we can.

If you need to move a decimal over 2 places, multiply the top and bottom by 100.

1 kilogram/2.2 pounds  =  x kilograms/1 pound

x  =  1/2.2  =  10/22  =  5/11

Question 13 :

If r is positive, and p is negative, which of the following must be negative ?

(A)  rp + 2  (B)  - |rp|  (C)  r2p2 - 10

(D)  -(r + p) (E)  (r + p)3

Solution :

Let us take option B, -|rp|

By multiplying positive and negative number, we get negative number. But the negative is in absolute sign, the answer will be positive.

In front of |rp|, we have negative sign. So the final answer will always be negative.

Question 14 :

If a is a positive integer, then what is the value of 5a + 5a + 1 ?

(A)  6a  (B)  5a - 1  (C)  52a + 1  (D)  (5a)a - 1  (E)  6(5a)

Solution :

=  5a + 5a + 1

=  5a + 5⋅ 5

=  5a(1 + 5)

=  5a ⋅ 6

=  65a

Question 15 :

X, Y and Z are points on a line in that order. XY is 20, and YZ is 15 more than XY. What is XZ ?

(A)  25  (B)  35  (C)  45  (D)  55  (E)  65

Solution :

XY  =  20

YZ  =  15 + 20  =  35

From this, we come to know that Y lies between X and Z

XZ  =  XY + YZ

=  20 + 35

=  55

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