Question 1 :

Find the area of the figure shown below. Question 2 :

Find the area of the figure shown below. Question 3 :

John bought a square plot of side 60 m. Adjacent to this David bought a rectangular plot of dimension 70 m x 50 m. Both paid the same amount. Who is benefited ?

Question 4 :

Find the area of the figure shown below. Question 5 :

Daniel bought a square plot of side 50 m. Adjacent to this Richard bought a rectangular plot of length 60 m and breadth 40 m for the same price. Find out who is benefited and how many sq. m. are more for him ?  Question 1 :

Find the area of the figure shown below.  By drawing a line GD parallel to AB, we can split the given picture as two parts.

(i) GDEF is a square of side length 3 cm

(ii) ABCG is a rectangle of length 10 cm and width 4 cm

Area of square  =  a2

Area of rectangle  =  length x breadth

Area of square (GDEF)  =  32  =  9 cm2

Area of rectangle  =  10 x 4  =  40 cm2

Area of the given figure  =  40 + 9  =  49 cm2

Question 2 :

Find the area of the figure shown below.  By drawing a line BD parallel to AE, we can split the given picture as two parts.

(i) BCD is a triangle

(ii) ABED is a rectangle

Area of triangle  =  (1/2) x b x h

Area of rectangle  =  length x breadth

Length of AC  =  17

AB + BC  =  17 -----> 10 + BC  =  17 -----> BC  =  7 cm

Area of triangle  =  (1/2) x 7 x 5  =  35/2  =   17.5 cm2

Area of rectangle  =  10 x 5  =  50 cm2

Area of given shape  =  17.5 + 50  =  67.5 cm2

Question 3 :

John bought a square plot of side 60 m. Adjacent to this David bought a rectangular plot of dimension 70 m x 50 m. Both paid the same amount. Who is benefited ?  To find who is benefited, we have to find the area of above shapes separately.

(i) ABFG is a square of side length 60 m

(ii) BCDE is a rectangle of length 70 m and width 50 m.

Area of square   =  a2

Area of rectangle  =  length x breadth

Area of ABFG  =  602  =  60 x 60  =  3600 m2

Area of rectangle  =  70 x 50  =  3500 m2

From the above calculation, we come to know that John is having more area than David. So John is more benefited.

Question 4 :

Find the area of the figure shown below.  (i)  ABCD is a square of side length 15 cm

(ii)  Area of rectangle FEGH

Length of DC  =  15

DF + FE + EC  =  15 -----> 3 + FE + 5  =  15

FE  =  15 - 8 -----> FE  =  7 cm

Area of square (ABCD)  =  a2  =  152  =  225 cm2

Area of rectangle (FEGH)  =  length x width

=  20 x 7

=  140 cm2

Area of the given figure  =  225 + 140  =  365 cm2

Question 5 :

Daniel bought a square plot of side 50 m. Adjacent to this Richard bought a rectangular plot of length 60 m and breadth 40 m for the same price. Find out who is benefited and how many sq. m. are more for him?

Area of land owned by Daniel  =  a2

=  502

=  50 x 50

=  2500 m2

Area of land owned by Richard  =  length x width

=  60 x 40

=  2400 m2

Because Daniel is having more area than Richard, we can decide that Daniel is benefited.

Daniel is having 100 m2 more area than Richard. Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.

You can also visit the following web pages on different stuff in math.

WORD PROBLEMS

Word problems on simple equations

Word problems on linear equations

Algebra word problems

Word problems on trains

Area and perimeter word problems

Word problems on direct variation and inverse variation

Word problems on unit price

Word problems on unit rate

Word problems on comparing rates

Converting customary units word problems

Converting metric units word problems

Word problems on simple interest

Word problems on compound interest

Word problems on types of angles

Complementary and supplementary angles word problems

Double facts word problems

Trigonometry word problems

Percentage word problems

Profit and loss word problems

Markup and markdown word problems

Decimal word problems

Word problems on fractions

Word problems on mixed fractrions

One step equation word problems

Linear inequalities word problems

Ratio and proportion word problems

Time and work word problems

Word problems on sets and venn diagrams

Word problems on ages

Pythagorean theorem word problems

Percent of a number word problems

Word problems on constant speed

Word problems on average speed

Word problems on sum of the angles of a triangle is 180 degree

OTHER TOPICS

Profit and loss shortcuts

Percentage shortcuts

Times table shortcuts

Time, speed and distance shortcuts

Ratio and proportion shortcuts

Domain and range of rational functions

Domain and range of rational functions with holes

Graphing rational functions

Graphing rational functions with holes

Converting repeating decimals in to fractions

Decimal representation of rational numbers

Finding square root using long division

L.C.M method to solve time and work problems

Translating the word problems in to algebraic expressions

Remainder when 2 power 256 is divided by 17

Remainder when 17 power 23 is divided by 16

Sum of all three digit numbers divisible by 6

Sum of all three digit numbers divisible by 7

Sum of all three digit numbers divisible by 8

Sum of all three digit numbers formed using 1, 3, 4

Sum of all three four digit numbers formed with non zero digits

Sum of all three four digit numbers formed using 0, 1, 2, 3

Sum of all three four digit numbers formed using 1, 2, 5, 6 