AREA OF COMPOSITE FIGURES WORKSHEET 7TH GRADE ANSWERS

Question 1 :

Find the area of the figure shown below. 

Question 2 :

Find the area of the figure shown below. 

Question 3 : 

John bought a square plot of side 60 m. Adjacent to this David bought a rectangular plot of dimension 70 m x 50 m. Both paid the same amount. Who is benefited ?

Question 4 :

Find the area of the figure shown below. 

Question 5 : 

Daniel bought a square plot of side 50 m. Adjacent to this Richard bought a rectangular plot of length 60 m and breadth 40 m for the same price. Find out who is benefited and how many sq. m. are more for him ?

Answers

1. Answer :

By drawing a line GD parallel to AB, we can split the given picture as two parts.

(i) GDEF is a square of side length 3 cm

(ii) ABCG is a rectangle of length 10 cm and width 4 cm

Area of square  =  a2

Area of rectangle  =  length x breadth

Area of square (GDEF)  =  32  =  9 cm2

Area of rectangle  =  10 x 4  =  40 cm2

Area of the given figure  =  40 + 9  =  49 cm2

2. Answer :

By drawing a line BD parallel to AE, we can split the given picture as two parts.

(i) BCD is a triangle

(ii) ABED is a rectangle 

Area of triangle  =  (1/2) x b x h

Area of rectangle  =  length x breadth

Length of AC  =  17

AB + BC  =  17 -----> 10 + BC  =  17 -----> BC  =  7 cm

Area of triangle  =  (1/2) x 7 x 5  =  35/2  =   17.5 cm2

Area of rectangle  =  10 x 5  =  50 cm2

Area of given shape  =  17.5 + 50  =  67.5 cm2

3. Answer :

To find who is benefited, we have to find the area of above shapes separately. 

(i) ABFG is a square of side length 60 m

(ii) BCDE is a rectangle of length 70 m and width 50 m.

Area of square   =  a2

Area of rectangle  =  length x breadth

Area of ABFG  =  602  =  60 x 60  =  3600 m2

Area of rectangle  =  70 x 50  =  3500 m2

From the above calculation, we come to know that John is having more area than David. So John is more benefited.

4. Answer :

(i)  ABCD is a square of side length 15 cm

(ii)  Area of rectangle FEGH  

Length of DC  =  15

DF + FE + EC  =  15 -----> 3 + FE + 5  =  15

FE  =  15 - 8 -----> FE  =  7 cm

Area of square (ABCD)  =  a2  =  152  =  225 cm2

Area of rectangle (FEGH)  =  length x width 

=  20 x 7

=  140 cm2

Area of the given figure  =  225 + 140  =  365 cm2

5. Answer :

Area of land owned by Daniel  =  a2

=  502

=  50 x 50

=  2500 m2

Area of land owned by Richard  =  length x width

=  60 x 40

=  2400 m2

Because Daniel is having more area than Richard, we can decide that Daniel is benefited.

Daniel is having 100 m2 more area than Richard.

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