Question 1 :
Find the value of x.
Question 2 :
Find the value of t.
Question 3 :
Find the value of a.
Question 4 :
Find the value of a.
Question 5 :
Find the value of a.
Question 6 :
Find the value of k.
Question 7 :
Find the value of a.
Question 8 :
Find the value of a.
Question 9 :
Find the value of a.
Question 10 :
Find the value of a.
Question 11 :
Find the value of a.
Question 12 :
Find the value of a.
1. Answer :
In the triangle shown above, by Angle Sum Property of Triangle,
x° + 2x° + 60° = 180°
3x + 60 = 180
Subtract 60 from both sides.
3x = 120
Divide both sides by 3.
x = 40
2. Answer :
In the triangle shown above, by Angle Sum Property of Triangle,
t° + t° + 90° = 180°
2t + 90 = 180
Subtract 90 from both sides.
2t = 90
Divide both sides by 2.
t = 45
3. Answer :
In the triangle shown above, by Angle Sum Property of Triangle,
a° + a° + 70° = 180°
2a + 70 = 180
Subtract 70 from both sides.
2a = 110
Divide both sides by 2.
a = 55
4. Answer :
In the diagram shown above, C and 98° are linear pair.
C + 98° = 180°
Subtract 98° from both sides.
C = 82°
In the triangle shown above, by Angle Sum Property of Triangle,
a° + a° + C = 180°
Substitute C = 82°.
a° + a° + 82° = 180°
2a + 82 = 180
Subtract 82 from both sides.
2a = 98
Divide both sides by 2.
a = 49
5. Answer :
In the diagram shown above, C and 120° are linear pair.
C + 120° = 180°
Subtract 120° from both sides.
C = 60°
In the triangle shown above, by Angle Sum Property of Triangle,
a° + 2a° + C = 180°
Substitute C = 60°.
a° + 2a° + 60° = 180°
3a + 60 = 180
Subtract 60 from both sides.
3a = 120
Divide both sides by 3.
a = 40
6. Answer :
In the diagram shown above, C and 110° are linear pair.
C + 110° = 180°
Subtract 110° from both sides.
C = 70°
In the triangle shown above, by Angle Sum Property of Triangle,
k° + k° + C = 180°
Substitute C = 70°.
k° + k° + 70° = 180°
2k + 70 = 180
Subtract 70 from both sides.
2k = 110
Divide both sides by 2.
k = 55
7. Answer :
In the diagram shown above, C and 125° are linear pair.
C + 125° = 180°
Subtract 125° from both sides.
C = 55°
In the triangle shown above, by Angle Sum Property of Triangle,
a° + 70° + C = 180°
Substitute C = 55°.
a° + 70° + 55° = 180°
a + 125 = 180
Subtract 125 from both sides.
a = 55
8. Answer :
In the diagram shown above, a° and C are linear pair.
a° + C = 180°
Subtract a° from both sides.
C = 180° - a°
In the triangle shown above, by Angle Sum Property of Triangle,
C + 90° + 35° = 180°
Substitute C = 180° - a°.
180° - a° + 90° + 35° = 180°
-a + 305 = 180
Subtract 305 from both sides.
-a = -125
Multiply both sides by -1.
a = 125
9. Answer :
In the diagram shown above, a° and C are linear pair.
a° + C = 180°
Subtract a° from both sides.
C = 180° - a°
In the triangle shown above, by Angle Sum Property of Triangle,
C + 45° + 101° = 180°
Substitute C = 180° - a°.
180° - a° + 45° + 101° = 180°
-a + 326 = 180
Subtract 326 from both sides.
-a = -146
Multiply both sides by -1.
a = 146
10. Answer :
In the diagram shown above, C and 132° are linear pair.
C + 132° = 180°
Subtract 132° from both sides.
C = 48°
In the triangle shown above, by Angle Sum Property of Triangle,
a° + 63° + C = 180°
Substitute C = 48°.
a° + 63° + 48° = 180°
a + 111 = 180
Subtract 111 from both sides.
a = 69
11. Answer :
In the diagram shown above, C and 63° are vertical angles.
C = 63°
In the triangle shown above, by Angle Sum Property of Triangle,
a° + 62° + C = 180°
Substitute C = 63°.
a° + 62° + 63° = 180°
a + 125 = 180
Subtract 125 from both sides.
a = 55
12. Answer :
In the diagram shown above, C and a° are vertical angles.
C = a°
In the triangle shown above, by Angle Sum Property of Triangle,
C + 40° + 90° = 180°
Substitute C = a°.
a° + 40° + 90° = 180°
a + 130 = 180
Subtract 130 from both sides.
a = 50
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