Adjoint of Matrix Questions 5
In this page adjoint of matrix questions 5 we are going to see solution of question 5 based on the topic ad-joint of matrix.
Question 5
Find the ad-joint of the following matrix
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Solution:
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minor of 4 |
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adjoint of matrix questions 5 |
= [0-4] = (-4) = -4 | |||||||||
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Cofactor of 4 |
= + (-4) = -4 |
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minor of 2 |
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= [0-8] = (-8) = -8 | ||||||||||
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Cofactor of 2 |
= - (-8) = 8 |
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minor of 1 |
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= [6-6] = (0) = 0 | ||||||||||
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Cofactor of 1 |
= + (0) = 0 |
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minor of 6 |
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= [0-1] = (-1) = -1 | ||||||||||
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Cofactor of 6 |
= - (-1) = 1 |
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minor of 3 |
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= [0-2] = (-2) = -2 | ||||||||||
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Cofactor of 3 |
= + (-2) = -2 |
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minor of 4 |
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= [4-4] = (0) = 0 | ||||||||||
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Cofactor of 4 |
= - (0) = 0 |
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minor of 2 |
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= [8-3] = (5) = 5 | ||||||||||
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Cofactor of 2 |
= + 5 |
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minor of 1 |
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= [16-6] = 10 | ||||||||||
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Cofactor of 1 |
= -(10) = -10 |
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minor of 0 |
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= [12-12] = 0 | ||||||||||
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Cofactor of 0 |
= +(0) = 0 |
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co-factor matrix = |
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adjoint of matrix= |
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- Cramer's Rule for 3 equations
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- Rank Method in Matrix
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