In this page adjoint of matrix questions 4 we are going to see solution of question 4 based on the topic adjoint of matrix.
Question 4
Find the adjoint of the following matrix

Solution:
minor of 1 


= [9(8)] = (9+8) = 1  
Cofactor of 1 
= + (1) = 1 
minor of 1 


= [612] = (6) = 6  
Cofactor of 1 
=  (6) = 6 
minor of 1 


= [4(9)] = (4+9) = 5  
Cofactor of 1 
= +(5) = 5 
minor of 2 


= [32] = (1) = 1  
Cofactor of 2 
=  (1) = 1 
minor of 3 


= [3(3)] = (3+3) = 6  
Cofactor of 3 
= + (6) = 6 
minor of 4 


= [23] = (5) = 5  
Cofactor of 4 
=  (5) = 5 
minor of 3 


= [43] = (1) = 1  
Cofactor of 3 
= +(1) = 1 
minor of 2 


= [4(2)] = (4+2) = 6  
Cofactor of 2 
= (6) = 6 
minor of 3 


= [32] = (5) = 5  
Cofactor of 3 
= +(5) = 5 
adjoint of matrix questions 4 adjoint of matrix questions 4
cofactor matrix = 


adjoint of matrix= 
