## Adjoint of Matrix Questions 4

In this page adjoint of matrix questions 4 we are going to see solution of question 4 based on the topic ad-joint of matrix.

Question 4

Find the ad-joint of the following matrix

 1 1 -1 2 -3 4 3 -2 3

Solution:

minor of 1

=
 -3 4 -2 3

= [-9-(-8)]

= (-9+8)

= -1

Cofactor of 1

=  + (-1)

=    -1

minor of 1

=
 2 4 3 3

= [6-12]

= (-6)

= -6

Cofactor of 1

=  - (-6)

=    6

minor of -1

=
 2 -3 3 -2

= [-4-(-9)]

= (-4+9)

= 5

Cofactor of -1

=  +(5)

=    5

minor of 2

=
 1 -1 -2 3

= [3-2]

= (1)

= 1

Cofactor of 2

=  - (1)

=    -1

minor of -3

=
 1 -1 3 3

= [3-(-3)]

= (3+3)

= 6

Cofactor of -3

=  + (6)

=    6

minor of 4

=
 1 1 3 -2

= [-2-3]

= (-5)

= -5

Cofactor of 4

=  - (-5)

=    5

minor of 3

=
 1 -1 -3 4

= [4-3]

= (1)

= 1

Cofactor of 3

=  +(1)

=    1

minor of -2

=
 1 -1 2 4

= [4-(-2)]

= (4+2)

= 6

Cofactor of -2

=  -(6)

=    -6

minor of 3

=
 1 1 2 -3

= [-3-2]

= (-5)

= -5

Cofactor of 3

=  +(-5)

=    -5

co-factor matrix =

 -1 6 5 -1 6 5 1 -6 -5

 -1 -1 1 6 6 -6 5 5 -5  