Adjoint of Matrix Questions 2
In this page adjoint of matrix questions 2 we are going to see solution of question 1 based on the topic ad-joint of matrix.
Question 2
Find the ad-joint of the following matrix
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Solution:
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minor of 1 |
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|||||||||
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= [4-3] = 1 | ||||||||||
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Cofactor of 1 |
= + (1) = 1 |
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minor of 2 |
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|||||||||
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= [4-2] = 2 | ||||||||||
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Cofactor of 2 |
= - (2) = -2 |
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minor of 3 |
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|||||||||
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= [3-2] = 1 | ||||||||||
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Cofactor of 3 |
= + (1) = 1 |
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minor of 1 |
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|||||||||
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= [8-9] = -1 | ||||||||||
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Cofactor of 1 |
= - (-1) = 1 |
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minor of 1 |
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|||||||||
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= [4-6] = -2 | ||||||||||
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Cofactor of 1 |
= + (-2) = -2 |
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minor of 1 |
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|||||||||
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= [3-4] = -1 | ||||||||||
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Cofactor of 1 |
= - (-1) = 1 |
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minor of 2 |
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|||||||||
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= [2-3] = -1 | ||||||||||
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Cofactor of 2 |
= + (-1) = -1 |
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minor of 3 |
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|||||||||
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= [1-3] = -2 | ||||||||||
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Cofactor of 3 |
= - (-2) = 2 |
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minor of 4 |
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|||||||||
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adjoint of matrix questions 2 |
= [1-2] = -1 | |||||||||
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Cofactor of 4 |
= + (-1) = -1 |
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co-factor matrix = |
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||||||||||||||||||||
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adjoint of matrix = |
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