In this page adjoint of matrix questions 2 we are going to see solution of question 1 based on the topic adjoint of matrix.
Question 2
Find the adjoint of the following matrix

Solution:
minor of 1 


= [43] = 1  
Cofactor of 1 
= + (1) = 1 
minor of 2 


= [42] = 2  
Cofactor of 2 
=  (2) = 2 
minor of 3 


= [32] = 1  
Cofactor of 3 
= + (1) = 1 
minor of 1 


= [89] = 1  
Cofactor of 1 
=  (1) = 1 
minor of 1 


= [46] = 2  
Cofactor of 1 
= + (2) = 2 
minor of 1 


= [34] = 1  
Cofactor of 1 
=  (1) = 1 
minor of 2 


= [23] = 1  
Cofactor of 2 
= + (1) = 1 
minor of 3 


= [13] = 2  
Cofactor of 3 
=  (2) = 2 
minor of 4 


adjoint of matrix questions 2 
= [12] = 1  
Cofactor of 4 
= + (1) = 1 
cofactor matrix = 


adjoint of matrix = 

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