In this page adjoint of matrix questions 1 we are going to see solution of question 1 based on the topic ad-joint of matrix.
Question 1
Find the ad-joint of the following matrix
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Solution:
minor of 2 |
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= [2-(-1)] = (2+1) = 3 | ||||||||||
Cofactor of 2 |
= + (3) = 3 |
minor of 1 |
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= [2-1] = 1 | ||||||||||
Cofactor of 1 |
= -(1) = -1 |
minor of 1 |
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= [-1-1] = -2 | ||||||||||
Cofactor of 1 |
= + (-2) = -2 |
minor of 1 |
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= [2-(-1)] = [2+1] = 3 = 3 | ||||||||||
Cofactor of 1 |
= - (3) = -3 |
minor of 1 |
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= [4-1] = 3 = 3 | ||||||||||
Cofactor of 1 |
= + (3) = 3 |
minor of 1 |
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= [-2-1] = -3 = -3 | ||||||||||
Cofactor of 1 |
= - (-3) = 3 |
minor of 1 |
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= [1-1] = 0 | ||||||||||
Cofactor of 1 |
= + (0) = 0 |
minor of -1 |
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= [2-1] = 1 | ||||||||||
Cofactor of -1 |
= - (1) = -1 |
minor of 2 |
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adjoint of matrix questions 1 adjoint of matrix questions 1 |
= [2-1] = 1 | |||||||||
Cofactor of 2 |
= + (1) = 1 |
co-factor matrix = |
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adjoint of matrix= |
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