ADDING AND SUBTRACTING MIXED FRACTIONS

We can add or subtract mixed fractions using the steps explained below.

Step 1 :

To add and subtract mixed fractions, first convert the mixed fractions to improper fractions.

Step 2 :

After converting the mixed fraction to an improper fraction, if the denominators are same, take the denominator once and combine the numerators.

If the denominators are different, we can make the denominators same using least common multiple.

Step 3 :

If the result of step 3 is an improper fraction, then convert it to a mixed fraction.

Example 1 :

Add 3 1/5 and 4 4/5.

Solution :

Convert the mixed fractions to improper fractions.

3 1/5 = 16/5

4 4/5 = 24/5

3 1/5 + 4 4/5 :

= 16/5 + 24/5

The fractions 16/5 and 24/5 have the same denominator. So, use the denominator once and combine the numerators.

= (16 + 24)/5

= 40/5

= 8

Example 2 :

Subtract 3 1/5 from 4 4/5.

Solution :

Convert the mixed fractions to improper fractions.

4 4/5 = 24/5

3 1/5 = 16/5

4 4/5 - 3 1/5 :

= 24/5 - 16/5

= (24 - 16)/5

= 8/5

= 1 3/5

Example 3 :

Add 2 1/5 and 1 3/4.

Solution :

Convert the mixed fractions to improper fractions.

2 1/5 = 11/5

1 3/4 = 7/4

The denominators of the fractions 11/5 and 7/4 are different.

Least common multiple of (5, 4) = 20.

To make the denominator as 20, multiply both numerator and denominator of the first fraction by 4 and the second fraction by 5.

11/5 = (11 ⋅ 4)/(5 ⋅ 4) = 44/20

7/4 = (7 ⋅ 5)/(4 ⋅ 5) = 35/20

2 1/5 + 1 3/4 :

= 11/5 + 7/4

= 44/20 + 35/20

= (44 + 35)/20

= 79/20

= 3 19/20

Example 4 :

Subtract 1 2/3 from 1 10/11.

Solution :

Convert the mixed fractions into improper fractions.

1 10/11 = 21/11

1 2/3 = 5/3

The denominators of the fractions 21/11 and 5/3 are different.

Least common multiple of (11, 3) = 33

To make the denominator as 33, multiply both numerator and denominator of the first fraction by 3 and the second fraction by 11.

21/11 = (21 ⋅ 3)/(11 ⋅ 3) = 63/33

5/3 = (5 ⋅ 11)/(3 ⋅ 11) = 55/33

1 10/11 - 1 2/3 :

= 21/11 - 5/3

= 63/33 - 55/33

= (63 - 55)/33

= 8/33

Example 5 :

Add 1 10/11 and 1 2/3.

Solution :

Convert the mixed fractions into improper fractions.

1 10/11 = 21/11

1 2/3 = 5/3

The denominators of the fractions 21/11 and 5/3 are different.

Least common multiple of (11, 3) = 33

To make the denominator as 33, multiply both numerator and denominator of the first fraction by 3 and the second fraction by 11.

21/11 = (21 ⋅ 3)/(11 ⋅ 3) = 63/33

5/3 = (5 ⋅ 11)/(3 ⋅ 11) = 55/33

1 10/11 + 1 2/3 :

= 21/11 + 5/3

= 63/33 + 55/33

= (63 + 55)/33

= 118/33

= 3 19/33

Example 6 :

Add 2 3/4 and 1 1/5.

Solution :

Convert the mixed fractions into improper fractions.

2 3/4 = 11/4

1 1/5 = 6/5

The denominators of the fractions 11/4 and 6/5 are different.

Least common multiple of (4, 5) = 20

To make the denominator as 20, multiply both numerator and denominator of the first fraction by 5 and the second fraction by 4.

11/4 = (11 ⋅ 5)/(4 ⋅ 5) = 55/20

6/5 = (6 ⋅ 4)/(5 ⋅ 4) = 24/20

2 3/4 + 1 1/5 :

= 11/4 + 6/5

= 55/20 + 24/20

= (55 + 24)/20

= 79/20

= 3 19/20

Example 7 :

Shannon needs 2  2/5 yards of the solid fabric for the bedspread and 2 7/8 yards of the solid fabric for the curtains. How much solid fabric does Shannon need for this project? 

Solution :

Quantity of fabric needed for bedspread = 2  2/5 yards

Quantity of fabric needed for curtains = 2  7/8 yards

Total quantity of fabric = 2  2/5 + 2  7/8

Adding the whole number and adding the fractions separately.

= (2 + 2) + (2/5 + 7/8)

= 4 + (16 + 35)/40

= 4 + 51/40

= 4 + 1 + 11/40

= 5  11/40

So, the required quantity of fabrics is 5  11/40 yards.

Example 8 :

Shannon needs a total of 6 yards of lining fabric for the curtains. She already has 2 7/12 yards of lining fabric. How much more lining fabric does she need?

Solution :

Let x be the required quantity of fabric.

x + 2  7/12 = 6

x + (24 + 7)/12 = 6

x + 31/12 = 6

x = 6 - (31/12)

x = (72 - 31)/12

x = 41/12

x = 3  5/12 yards

So, the required quantity is 3  5/12 yards.

Example 9 :

Miguel bought 2  1/4 pounds of hamburger, 1  1/5 pounds of sliced turkey, and 2 pounds of cheese. What was the total weight of all of his purchases?

Solution :

Quantity of hamburger = 2  1/4 pounds

Quantity of sliced turkey = 1  1/5 pounds

Quantity of cheese = 2 pounds

Total weight = 2  1/4 + 1  1/5 + 2

= (2 + 1 + 2) + 1/4 + 1/5

= 5 + 9/20

= 5  9/20

So, the total weight is 5  9/20 pounds.


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