# SHSAT MATH PRACTICE TEST QUESTIONS

Question 1 :

Thirty of the fifty students who took an exam received a grade of 90%  or greater.  What percentage of those fifty students received a grade of less than 90%?

(A)  70  (B)  35  (C)  40  (D)  30  (E)  10

Solution :

Total number of students  =  50

Number of students scored 90% or

more than 90% marks   =  30

Percentage of students who score

more than 90% of marks  =  (30/50) ⋅ 100%

=  60%

So, 60% of students are scoring 90% or more than 90% of marks.

Hence 40% students are getting lesser than 90% marks.

Question 2 :

Let n be a number from -3 to 4 inclusive.  What is the range of values of n2?

(A)  -9 ≤ n2 ≤ 16  (B)   9 ≤ n2 ≤ 16  (C)  3 ≤ n2 ≤ 4

(D)  0 ≤ n2 ≤ 2  (E)  0 ≤ n2 ≤ 16

Solution :

 n = -3n2  =  9 n = -2n2  =  4 n = -1n2  =  1 n = 0n2  =  0 n = 1n2  =  1 n = 2n2  =  4 n = 3n2  =  9 n = 4n2  =  16

The range of n2 lies between 9 to 16 (inclusive).

Question 3 :

A is 3 times C.  B is 8 less than C.  For what value of C does A = B?

(A)  -4  (B)  0  (C)  1  (D)  2  (E)  5/2

Solution :

Given that :

A  =  3 C

B  =  C - 8

A  =  B

3 C   =  C - 8

3C - C  =  -8

2C  =  -8

C  =  -4

Question 4 :

In a class of 28 students, everyone likes math, English, or both.  If 17 like math and 19 like English, how many like both?

(A)  2  (B)  8  (C)  16  (D)  20  (E)  28

Solution :

Number of students in a class  =  28

Number of students who like math  =  17

Number of students who like English  =  19

Number of students who like at least one  =  28

17 - x + x + 19 - x  =  28

36 + x  =  28

x  =  28 - 36

x  =  8

Hence the number of students who like both subject is 8.

Question 5 :

Let x = 32·53·74 and y = 23·3·52.  What is the greatest common factor of and y?

(A)  2· 3 · 5 · 7  (B)  2· 3· 5· 74  (C)  3 · 5

(D)  3 · 52  (E)  32·53

Solution :

x = 32·53·74 and y = 23·3·52

Common factors are 3 · 52.

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