**SHSAT Math Mixed Practice Questions :**

Here we are going to see some practice questions questions for SHSAT exams. Each question paper consists of 20 question. For each questions, you can find solution with detailed explanation.

SHSAT Math Mixed Practice Questions

**Question 1 :**

(3 + 4)^{2} =

(A) 13 (B) 14 (C) 19 (D) 25 (E) 49

**Solution :**

= (3 + 4)^{2}

= 7^{2}

= 49

Hence the answer is 49.

**Question 2 :**

The exact value of √49 - √24 is

(A) 2 (B) between 2 and 5 (C) 5 (D) more than 5

(E) The expression does not have an exact value.

**Solution :**

= √49 - √24

= 7 - √(2⋅2⋅2⋅3)

= 7 - 2√6

The answer is between 2 and 5.

**Question 3 : **

200% of 7 is

(A) .14 (B) 7 (C) 14 (D) 21 (E) 1,400

**Solution :**

= 200% of 7

= (200/100) ⋅ 7

= 14

Hence the answer is 14.

Question 4 :

(All line segments are either horizontal or vertical, as shown.) The perimeter of the figure is

(A) 5 (B) 6 (C) 7 (D) 12 (E) 14

**Solution :**

The two unmarked vertical side must add upto 3, and two unmarked horizontal sides must add upto 4.

Perimeter = 3. + 4 + 3 + 4 = 14

Hence the perimeter is 14.

**Question 5 :**

What is the value of N if (1/5) – (1/6) = 1/N?

(A) 7 (B) 30 (C) 1/30 (D) -30 (E) -1/30

**Solution :**

** = (1/5) – (1/6)**

Since the denominators are not same, we have to take L.C.M.

** = (6 - 5)/30**

** = 1/30**

**Hence the value of N is 30.**

**Question 6 :**

Find the value of (2^{4} – 4^{2}) + (2^{3 }– 3^{2})

(A) -11 (B) -8 (C) -1 (D) 0 (E) 1

**Solution :**

= (2^{4} – 4^{2}) + (2^{3 }– 3^{2})

= (16 - 16) + (8 - 9)

= 0 + (-1)

= -1

Hence the answer is -1.

**Question 7 :**

On the number line shown, Q (not shown) is the midpoint of PR. What is the midpoint of QS?

(A) -5 (B) -4 (C) 0 (D) 1 (E) 8

**Solution :**

Midpoint of PR = Q

Distance between PR :

-8 to -6 = -2 units, -6 to -4 = -2 units, -4 to -2 = -2 units,

-2 to 0 = -2 units, 0 to 2 = 2 units.

Midpoint of PR, Q = -6/2 = -3

S is located on 5.

Q is located on -3

Midpoint of QS = (-3 + 5)/2 = 2/2 = 1

**Question 8 :**

The ratio of boys to girls at a dance was 2 to 3. If 45 girls attended, what is the number of boys who attended?

(A) 9 (B) 18 (C) 27 (D) 30 (E) 45

**Solution :**

Ratio of boys to girls = 2 : 3

Number of girls attended = 45

2x + 3x = 5x

5x = 45

x = 9

Number of boys attended = 2(9) = 18

Hence the number of boys is 18.

**Question 9 :**

If the measure of angle A is 40°, then x + y =

(A) 80° (B) 120° (C) 180° (D) 220° (E) 360°

**Solution :**

Let the other interior angles of triangle be "p" and "q"

x + p = 180

y + q = 180

x + p + y + q = 180 + 180

x + y + (p + q) = 360 ---(1)

p + q + 40 = 180

p + q = 180 - 40 = 140

Applying the value of p + q in (1), we get

x + y + 140 = 360

x + y = 360 - 140

x + y = 220

Hence the answer is 220.

**Question 10 :**

If 6x is increased by 4y, and the sum is divided by 2, the result is equivalent to

(A) 3x + 4y (B) 6x + 2y (C) 3x + 2y

(D) (10x + y)/2 (E) 5(x + y)

**Solution :**

By converting the given statement "6x is increased by 4y, and the sum is divided by 2" into expression. We get

= (6x + 4y) / 2

= 2(3x + 2y) / 2

= 3x + 2y

Hence the answer is 3x + 2y.

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