PSAT MATH PRACTICE ONLINE
About "PSAT Math Practice Online"
PSAT Math Practice Online :
Here we are going to see some sample questions for PSAT exams. For each and every questions, you will have solutions with step by step explanation.
PSAT Math Practice Online
PSAT Math Practice Online - Practice questions
Question 1 :
If 2000/2x = 10, then what is √x?
Solution :
2000/2x = 10
1000/x = 10
x = 1000/10
x = 100
Taking square roots on both sides, we get
√x = √100
√x = 10
Question 2 :
If x = 9, y = -9 and z = -1, what is the value of yz + √x + yz - √x ?
Solution :
First let us simplify
yz + √x + yz - √x
= 2yz
By applying the value of y and z, we get
= 2(-9) (-1)
= 18
Question 3 :
1 dollar = 0.5 pillets
4 coss = 1 dollar
Lindsey has $20 to spend. She needs to buy exactly 2 pillets. She spends the remaining amount buying coss. How many coss does Lindsey purchase ?
Solution :
1 dollar = 0.5 pillets ----(1)
Lindsey wants to buy 2 pillets,
0.5/2 = 4
Multiplying (1) by 4, we get
4 dollar = 2 pillets
So, she spends 4 dollar to purchase 2 pillets. The remaining amount that she has = 20 - 4 = 16
Cost of 4 coss = 1 dollar
Number of coss purchased for 16 dollars
= 16(4)
= 64 coss
Question 4 :
√100 ÷ √25 =
Solution :
= √100 ÷ √25
= √(100/25)
= √4
= 2
Question 5 :
If x = -8, what is the value of (1/2) |4x - 4|?
Solution :
= (1/2) |4x - 4|
Applying the value of x in the expression, we get
= (1/2) |4(-8) - 4|
= (1/2) |-32-4|
= (1/2) (36)
= 18
Hence the answer is 18.
Question 6 :
Triangle NPQ is an equilateral triangle. If its perimeter is 27, what is the length of NP + NQ ?
Solution :
To find the perimeter of the triangle, we have to find the sum of all the sides.
NP + NQ + PQ = 27
x + x + x = 27
3x = 27
x = 27/3 = 9
NP + PQ = 9 + 9 = 18
Question 7 :
If 40% of x is 160, what is x ?
Solution :
40% of x = 160
(40/100) ⋅ x = 160
x = 160 (100/40)
x = 400
Question 8 :
When d is divided by 7, the remainder is 5, what is the remainder when d + 1 is divided by 7 ?
Solution :
Let d = 12
Here we choose 12, because it is greater than 7, when we divide 12 by 7, we get the remainder 5.
Then d + 1 = 12 + 1 = 13
By dividing this d + 1 by 7, we get 6(5 + 1) as remainder.
Hence the answer is 6.
Note : The number chosen should be 5 more than the multiple of 7.
Question 9 :
In the figure above, O is the center of the square. What is the area of the square ?
Solution :
Side length of square is 4 units.
Area of square = a2
= 42
= 16 square units.
Question 10 :
If O is the midpoint of PW, then what is the distance of OE?
Solution :
P(-13, 0) W(-3, 0)
O is the midpoint of PW
= (x1 + x2)/2, (y1 + y2)/2
= (-13-3)/2, (0+0)/2
= O (-8, 0)
E (3, 0)
OE = √(x2 - x1)2 + (y2 - y1)2
OE = √(-8-3)2 + (0-0)2
OE = √(-11)2
= 11
After having gone through the stuff given above, we hope that the students would have understood "PSAT Math Practice Online".
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WORD PROBLEMS
HCF and LCM word problems
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Markup and markdown word problems
Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
Word problems on sum of the angles of a triangle is 180 degree
OTHER TOPICS
Time, speed and distance shortcuts
Ratio and proportion shortcuts
Domain and range of rational functions
Domain and range of rational functions with holes
Graphing rational functions with holes
Converting repeating decimals in to fractions
Decimal representation of rational numbers
Finding square root using long division
L.C.M method to solve time and work problems
Translating the word problems in to algebraic expressions
Remainder when 2 power 256 is divided by 17
Remainder when 17 power 23 is divided by 16
Sum of all three digit numbers divisible by 6
Sum of all three digit numbers divisible by 7
Sum of all three digit numbers divisible by 8
Sum of all three digit numbers formed using 1, 3, 4
Sum of all three four digit numbers formed with non zero digits
