**9th Grade SHSAT Practice Test with solutions :**

Here we are going to see some practice questions questions for SHSAT exams.

SHSAT Math Test with Solution

To find questions from 1 to 5, please visit the page "SHSAT Math Practice for 9th Graders"

To find questions from 6 to 10, please visit the page "SHSAT Math Test with Answers"

To find questions from 11 to 15, please visit the page "SHSAT Math Test with Solution"

**Question 16 :**

Maria, Anoki, and Boris are teenagers, and the sum of their ages now is 49. The sum of their ages 8 years from now will be F, and the sum of their ages 10 years ago was P. The value of F – P is

(A) 54 (B) 18 (C) 17 (D) 6 (E) 2

**Solution :**

Sum of ages of Maria, Anoki and Boris = 49

Sum of their ages 8 years from now = 49 + 8 + 8 + 8

F = 73

Sum of their ages 10 years ago = 49 - 10 - 10 - 10

= 49 - 30

P = 19

F - P = 73 - 19

= 54

Hence the value of F - P is 54.

**Question 17 :**

If (1/4) + (1/x) = 1, then x =

(A) 1/8 (B) 2/3 (C) 4/3 (D) 2 (E) 3

**Solution :**

**(1/4) + (1/x) = 1**

**(x + 4) / 4x = 1**

**x + 4 = 4x **

**Subtract x on both sides**

**-3x + 4 = 0**

**Subtract 4 on both sides,**

**-3x = -4**

**x = 4/3**

**Hence the value of x is 4/3.**

**Question 18 :**

When the integer N is divided by 7, the quotient is Q and the remainder is 5. When N + 24 is divided by 7, the remainder is ‘

(A) 4 (B) 3 (C) 2 (D) 1 (E) 0

**Solution :**

Let us choose a number which gives the remainder 5 by dividing it by 7.

Let N = 12, by dividing 12 by 7, we get 5 as remainder.

By adding 12 by 24, we get 6. Now let us divide 36 by 7, we get the remainder 1.

Hence 1 is the answer.

**Question 19 :**

Point B is on line segment AD, and point E is on line segment BC. The value of x is

(A) 20 (B) 40 (C) 50 (D) 60 (E) 70

**Solution :**

In triangle ABC,

<A + <ABC + <C = 180

50 + <ABC + 70 = 180

<ABC = 180 - 120 = 60

In triangle EBD,

<EBD + <BDE + <DEB = 180

120 + 20 + x = 180

x = 180 - 140

x = 40

Hence the required angle is 40.

**Question 20 :**

Three-fourths of a number is equal to L. What is three-halves of that original number, in terms of L?

(A) 4/3L (B) 3/2L (C) 2L (D) 3L (E) 4L

**Solution :**

Let the number be "N"

(3/4) of N = L --(1)

= (3/2) of N

Form (1), N = 4L/3

= (3/2) (4L/3)

= 2 L

Hence the answer is 2 L.

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