## 6TH GRADE MATH PRACTICE QUESTIONS

6th Grade Math Practice Questions :

In this section, we will see some practice problems for 6th grade students.

Question 1 :

The sum of (-12) and (5) is

(A) 6     (B) 8      (C) -7

Solution :

=  -12 + 5

=  -7

Question 2 :

The perimeter of the equilateral triangle is 18. Find the length of each

(A) 5         (B) 4       (C) 6

Solution :

In equilateral the length of all sides will be equal.

3a  =  18

a  =  18/3

a  =  6

Hence the length of each side is 6.

Question 3 :

How to express 5 x 5 x 5 using exponent?

(A) 103        (B) 53           (C) 23

Solution :

5 x 5 x 5  =  53

Question 4 :

What is the value of 010

(A) 0       (B) 1       (C) 2

Solution :

010 means, we should multiply 0 ten times. So the answer is 0.

Question 5 :

A father is 30 years older than his son, and one year ago he was four times as old as his son. Find the father’s present ages.

(A) 53      (B) 12       (C) 41

Solution :

Let x be the son's age

Father's age  =  x + 30

One year ago,

Age of father  =  x + 30 - 1  ==>  x + 29

Son's age  =  x - 1

x + 29  =  4(x - 1)

x + 29  =  4x - 4

3x  =  33

x  =  11

Age of son  =  11 years

Age of father  =  30 + 11  ==> 41 years

Question 6 :

A perimeter of a square is 20 inches.Find the side length of the square.

(A) 10 inch        (B) 4 inch      (C) 5 inch

Solution :

The perimeter of the square  =  20 inches

4a  =  20

a  =  20/4

a  =  5

Question 7 :

A triangle has sides of lengths 19, 3 and 18 meters. What type of triangle is it?

(A) Equilateral       (B) Right        (C) Scalene

Solution :

Each side is having different lengths. Hence it is scalane triangle.

Question 8 :

The measure of an angle is 77°. What is the measure of a supplementary angle ?

(A) 105°      (B) 103°        (C) 50°

Solution :

Supplementary angle means the sum of the angles will be 180 degrees.

Let the required angle be x.

x + 77  =  180

x  =  180 - 77

x  =  103

Question 9 :

Find the 21st term in the sequence 2, 4, 6, 8 . . .

(A) 10       (B) 42         (C) 20

Solution :

By observing the above sequence, it is arithmetic progression.

an  =  a + (n - 1) d

First term (a)  =  2

common difference (d)  =  t2 - t1

=  4 - 2

d  =  2

a12  =  2 + (12 - 1)2

=  2 + 11(2)

=  2 + 22

=  24

Question 10 :

A train is traveling at the rate of 1 mile per 1 minute and 20 seconds. If the train continues at this rate, how many miles will it travel in one hour?

(A) 10 miles       (B) 15 miles         (C) 45 miles

Solution :

Let us convert minutes into seconds.

1 minute  =  60 seconds

60 + 20  =  80 seconds

A train is taking 80 seconds to travel one mile. In one hour there are 3600 seconds.

1 mile  =  80 seconds

1 second  =  1/80 mile

3600 second  =  360 ⋅ (1/80)

=  45 miles

After having gone through the stuff given above, we hope that the students would have practiced problems in the worksheet.

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