5th Grade Math Test Online :

In this section, we will see some practice problems for 5th grade students.

Question 1 :

Find the value of mn + x2 + y2. When x  =  2, y  =  1, m  =  2 and n  =  0.

(A)  5     (B)  10      (C)  15

Solution :

mn + x2 + y =  2(0) + 22 + 12

  =  5

Question 2 :

The sign of the product of a positive number and a negative number is always __________

(A) Positive   (B) Negative    (C) Zero

Solution :

The product of positive number and negative number is always a negative number.

Question 3 :

Write the following fractions in numerals.

(A) 5/4   (B) 4/5   (C) 1/5

Solution :

5/4  =  Five fourth

4/5  =  Four fifth

1/5  =  One fifth

Question 4 :

Reduce 18/20 to its lowest form.

(A) 9/10   (B) 8/5     (C) 5/10 

Solution :

We can divide 18 and 20 using 2 times table.

18/20  =  9/10

Hence the simplified form is 9/10.

Question 5 :

Three pieces of pipe weight 10.5 kg, 11.42 kg and 26.5 kg.What is the total weight of the three pieces of pipe?.

(A) 48.42 kg    (B) 57.52 kg     (C) 30.10 kg

Solution :

Total weight of pipe  =  10.5 + 11.42 + 26.5

  =  48.42 kg

Question 6 :

A wire measures 0.12 meters. If you cut it into 3 pieces of equal length, how long will each piece be?

(A) 0.02 m     (B) 0.06 m     (C) 0.04 m

Solution :

Length of wire  =  0.12 m

He is going to cut the wire into three equal pieces.

Length of each piece of pipe  =  0.12/3

  =  0.04 m

So, the length of each pipe is 0.04 m.

Question 7 :

The sum of one set of alternate digits and sum of the other set of alternate digits, differ by 0 or 1 or multiple of 11. Then the number is divisible by ______

(A) 9      (B) 11     (C) 15

Solution :

If a number is divisible by 11, it is also divisible by 11.

Question 8 :

The product of two numbers is 288. Their L.C.M is 144. What is their G.C.D? 

(A) 4     (B) 6      (C) 2

Solution :

Relationship between LCM and GCD is 

Product of two numbers  =  LCM x GCD

288  =  144 ⋅ x

x  =  288/144

x  =  2

Hence the GCD is 2.

Question 9 :

The perimeter of a rectangular garden is 800 m. If the length of the garden is 250 m, find the area of the garden in hectares.

(A) 3.75    (B) 3.2      (C) 10.5

Solution :

Perimeter of the rectangular garden  =  800 m

length of the garden  =  250 m

2 (l + w)  =  800

250 + w  =  800/2

250 + w  =  400

w  =  400 - 250

w  =  150

Area of garden  =  l w

=  250(150)

=  37500

Area of garden in hectares  =  37500/10000

=  3.75 hectares

Question 10 :

The volume of a cuboid is 118 cu.cm. If the length is 5.5 m and the breadth is 2.8 m. Find the height of the box.

(A)  7.6 cm      (B) 6.2 cm      (C) 5.4 cm

Solution :

Length  =  5.5 m, breadth  =  2.8 m and height  =  ?

Volume of cuboid  =  118 

⋅ b ⋅ h  =  118

5.5 (2.8) h  =  118

h  =  118/15.4

h  =   7.6

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