Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
To apply the concept given below, the given equations will be in the form
a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
(i) a1/a2 ≠ b1/b2, we get a unique solution
(ii) a1/a2 = a1/a2 = c1/c2, there are infinitely many solutions.
(iii) a1/a2 = a1/a2 ≠ c1/c2, there is no solution
On comparing the ratios a₁/a₂, b₁/b₂ and c₁/c₂, find out whether the following pair of linear equations are consistent or inconsistent.
Example 1 :
3 x + 2 y = 5 and 2 x - 3 y = 7
Solution :
3 x + 2 y – 5 = 0
2 x - 3 y - 7 = 0
From the given equations, let us find the values of a1, a2, b1, b2, c1 and c2
a1 = 3, b1 = 2, c1 = -5
a2 = 2, b2 = -3, c2 = -7
a1/a2 = 3/2 -------(1)
b1/b2 = 2/3 -------(2)
c1/c2 = -5/-7 = 5/7 -------(3)
This exactly matches the condition a₁/a₂ ≠ b₁/b₂.
Hence the system of equations is consistent.
Example 2 :
2 x - 3 y = 8 and 4 x - 6 y = 9
Solution :
2 x - 3 y – 8 = 0
4 x - 6 y -9 = 0
From the given equations, let us find the values of a1, a2, b1, b2, c1 and c2
a1 = 2, b1 = -3, c1 = -8
a2 = 4, b2 = -6, c2 = -9
a1/a2 = 2/4 = 1/2 -------(1)
b1/b2 = (-3)/(-6) = 1/2 -------(2)
c1/c2 = -8/(-9) = 8/9 -------(3)
This exactly matches the condition a₁/a₂ = b₁/b₂ ≠ c₁/c₂
From this we can decide that the two lines are parallel. It means these two lines will not intersect each other. So it is inconsistent.
Example 3 :
(3/2) x + (5/3) y = 7 and 9 x - 10 y = 14
Solution :
(3/2) x + (5/3) y – 7 = 0
9 x - 10 y – 14 = 0
From the given equations, let us find the values of a1, a2, b1, b2, c1 and c2
a1 = 3/2, b1 = 5/3, c1 = -7
a2 = 9, b2 = -10, c2 = -14
a1/a2 = (3/2) / 9 = 1/6 -------(1)
b1/b2 = (5/3)/(-10) = -1/6 -------(2)
c1/c2 = -7/(-14) = 1/2 -------(3)
This exactly matches the condition a₁/a₂ ≠ b₁/b₂
From this, we can decide the two lines are intersecting. So it is consistent.
Example 4 :
(4/3)x + 2y = 8 and 2x + 3y = 12
Solution :
(4/3) x + 2 y – 8 = 0
2 x + 3 y – 12 = 0
From the given equations, let us find the values of a1, a2, b1, b2, c1 and c2
a1 = 4/3, b1 = 2, c1 = -8
a2 = 2, b2 = 3, c2 = -12
a1/a2 = (4/3) / 2 = 2/3 -------(1)
b1/b2 = 2/3 -------(2)
c1/c2 = -8/(-12) = 2/3 -------(3)
This exactly matches the condition a₁/a₂ = b₁/b₂ = c₁/c₂
From this we may decide the two lines are coincident. So it is consistent.
Example 5 :
5y = 10x + 11
−5y = 5x − 21
The solution to the given system of equations is (x,y). What is the value of 30x?
Solution :
5y = 10x + 11 ------(1)
−5y = 5x − 21 ------(2)
Applying the value of 5y from (1), we get
-(10x + 11) = 5x - 21
-10x - 11 = 5x - 21
-10x - 5x = -21 + 11
-15x = -10
x = 10/15
x = 2/3
Solving for 30x = 30(2/3)
= 20
So, the value of 30x is 20.
Example 6 :
The pair of linear equations 2x + 3y = 5 and 4x + 6y = 10 is
(a) inconsistent (b) consistent
(c) dependent consistent (d) none of these
Solution :
2x + 3y = 5 ------(1)
4x + 6y = 10 ------(2)
3y = -2x + 5
y = (-2/3)x + 5/3
6y = -4x + 10
y = (-4x/6) + (10/6)
y = (-2x/3) + (5/3)
Since the above lines are having same slope and same y-intercept, the system of equations are consistent and it has infinitely many solution.
Example 7 :
The pair of equations y = 0 and y = –7 has
(a) one solution (b) two solutions
(c) infinitely many solutions (d) no solution
Solution :
y = 0 and y = –7
These lines are parallel, they will never meet. So, it has no solution.
Example 8 :
The pair of equations x = 4 and y = 3 graphically represents lines which are
(a) parallel (b) intersecting at (3, 4)
(c) coincident (d) intersecting at (4, 3)
Solution :
x = 4 is a line which is perpendicular to the x-axis.
y = 3 is the line which is parallel to the x axis.
The lines will intersect at the point (4, 3). Option d is correct.
Example 9 :
A pair of linear equations which has a unique solution x = 2, y = –3 is
(a) x + y = –1; 2x – 3y = –5
(b) 2x + 5y = –11; 4x + 10y = –22
(c) 2x – y = 1 ; 3x + 2y = 0
(d) x – 4y – 14 = 0; 5x – y – 13 = 0
Solution :
Option (a) :
x + y = –1; 2x – 3y = –5
Applying x = 2 and y = -3, we get
|
2 - 3 = -1 -1 = -1 True |
2(2) - 3(-3) = -5 4 + 9 = -5 13 ≠ -5 False |
Option a is not system of linear equation which has the solution (2, -3).
Option (b) :
2x + 5y = –11; 4x + 10y = –22
Applying x = 2 and y = -3, we get
|
2(2) + 5(-3) = 11 4 - 15 = -11 -11 = -11 |
4(2) + 10(-3) = -22 8 - 30 = -22 -22 = -22 |
Option b is correct.
Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
About Us | Contact Us | Privacy Policy
©All rights reserved. onlinemath4all.com
Dec 20, 25 10:51 AM
Dec 20, 25 10:49 AM
Dec 20, 25 10:49 AM