Word Problem Solution4





In this page word problem solution4 we are going to see solution for first word problem of the worksheet cross multiplication method.

Formulate the following problems as a pair of equations,and hence find their solutions:

(ii)  Three chairs and two tables cost $700 and five chairs and three tables cost $1100.What is the total cost of 2 chairs and 3 tables.

Solution:

Let x be the cost of one chair

Let y be the cost of one table

To form the first equation we have to consider this particular information from the question that is three chairs and two tables cost $700

         3 x + 2 y = 700  ----- (1)

To form the first equation we have to consider this particular information from the question that is five chairs and three tables cost $1100

         5 x + 3 y = 1100  ----- (2)

Multiply the first equation by 3 we get

                       9 x + 6 y = 2100

Multiply the second equation by 2 we get

                       10 x + 6 y = 2200 

                       9 x + 6 y = 2100

                       10 x + 6 y = 2200

                      (-)      (-)     (-)

                     ---------------------------

                         -x   = -100

                          x = 100

Substitute x = 100 in the first equation we get

3 x + 2 y = 700

3 (100) + 2 y = 700

300 + 2 y = 700

           2 y = 700 - 300

            2 y = 400

              y = 400/2

              y = 200

Therefore the cost of one chair = $100

Cost of one table = $200

Verification:

3 x + 2 y = 700

3(100) + 2(200) = 700

300 + 400 = 700

700 = 700

word problem solution4  word problem solution4


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