In this page two point form question11 we are going to see some
practice questions in the form of quiz.We have several ways to find the
equation.We have shown four ways.A
linear equation or an equation of the first degree in x and y represents
a straight line.The equation of a straight line is satisfied by the
co-ordinates of every point lying on the straight line and not by any
other point outside the straight line.

**Two point form:**

** (y-y1)/(y2-y1) = (x-x1)/(x2-x1)**

**Here (x1,y1) and (x2,y2) are the points on the line.**

If we have any two points on the line we can use this formula to find the equation.

**Question 1 : **two point form question11

**Find the ****equation of the line which is passing through the points (1,4) and (3,-2). **

**Question 2 :**

**Find the ****equation of the line which is passing through the points (0,4) and (3,1). **

**Question 3 :**

**Find the ****equation of the line which is passing through the points (3,1) and (-3,2). **

**Question 4 :**

**Find the ****equation of the line which is passing through the points (2,6) and (1,2). **

**Question 5 :**

**Find the ****equation of the line which is passing through the points (5,-5) and (2,7). **

**Question 6 :**

**Find the ****equation of the line which is passing through the points (1,3) and (0,7). **

**Question 7 :**

**Find the ****equation of the line which is passing through the points (2,-8) and (-5,2). **

**Question 8 :**

**Find the ****equation of the line which is passing through the points (3,0) and (4,-1). **

**Question 9 :**

**Find the ****equation of the line which is passing through the points (-1,-5) and (-3,-1). **

**Question 10 :**

**Find the ****equation of the line which is passing through the points (0,-5) and (4,-6). **

**Question 11 :**

**Find the ****equation of the line which is passing through the points (4,-3) and (0,-2). **

**Solution:**

Here (x₁,y₁) = (4,-3) and (x₂,y₂) = (0,-2)

Equation of a line:

** (y-y**₁**)/(y****₂-y****₁) = (x-x****₁)/(x****₂-x****₁)**

(y-(-3))/(-2-(-3)) = (x-4)/(0-4)

(y+3)/(-2+3) = (x-4)/(-4)

(y+3)/1 = (x-4)/(-4)

-4(y+3) = 1(x-4)

-4y - 12 = 1 x - 4

x + 4y + 12 - 4 = 0

x + 4y + 8 = 0

**Question 12 :**

**Find the ****equation of the line which is passing through the points (2,-1) and (-1,-7). **