## Solution1 of Multiplication Rules

**Online Math Tutoring by Expert Indian Math Tutor**

**ACT, SAT, Pre SAT, SCAT, SHSAT, ISEE and More.**

**Tutoring Charges $10 per hour**

**No credit card required**

**Free demo for 30 minutes**

**Mail us : v4formath@gmail.com **

**Skype id : rams_tpt**

**Mobile : +919994718681**

The page solution1 of multiplication rules is going to explain some example problems of the concept fundamental rules of counting.

**Question 1:**

In a class there are 27 boys and 14 girls. The teacher wants
to select 1 boy and 1 girl to represent a competition. In how many ways can the
teacher make this selection?

**Solution:**

In a class there are 27 boys and 14 girls. The teacher wants
to select 1 boy and 1 girl to represent a competition.

To solve this problem we have to select 1 boy and 1 girl.
Here both jobs have to be completed.

Number of ways to make this selection = 27 x 14

= 378

So there are 378 ways to select 1 boy and 1 girl.

**Question 2:**

Given 7 flags of different colours, how many different
signals can be generated if a signal requires the use of two flags, one below
the other?

**Solution:**

In this problem we have to select two flags one below the
other. To solve this problem we have to use multiplication rule. Because we must
select two flags,

Total number of flags = 7

Flag 1 Flag 2

We cannot use selected flag again. We have to use the
different flag for flag 2.

For the first place we have 7 options

For the second place we have only 6 options

Number of ways to select two flags = 7 x 6

= 42

solution1 of multiplication rules solution1 of multiplication rules

**Question 3:**

A person wants to buy one fountain pen, one ball pen and one
pencil from a stationery shop. If there are 10 fountain pen varieties, 12 ball
pen varieties and 5 pencil varieties, in how many ways can he select these
articles?

**Solution:**

Number of fountain pen = 10

Number of ball pen = 12

Number of pencil = 5

Number of ways for selecting 1 fountain pen = 10

Number of ways for selecting 1 ball pen = 12

Number of ways selecting 1 pencil = 5

Number of ways for selecting 1 fountain pen, ball pen,

and
pencil = 10 x 12 x 5

= 600 Therefore number of ways of selecting 1 fountain pen, 1 ball
pen, and 1 pencil = 600