RATIO AND PROPORTION PROBLEMS FOR CLASS 6
Ratio and Proportion Problems for Class 6 :
In this section, we are going to see the problems on ratio and proportion for class 6.
Ratio and Proportion Problems for Class 6
Problem 1 :
If there are two lengths such that a = 90 cm and b = 120 cm, then find the ratio between them.
Solution :
a : b = 90 : 120
a : b = 3 : 4
Hence, the ratio between the two lengths is
3 to 4
From question no. 2 to question no.8, please use the information in the table given below.
Problem 2 :
Find the ratio of the age of John to David.
Solution :
Age of John = 17 years
Age of David = 15 years
Age of John : Age of David = 17 : 15
Hence, the ratio of the age of John to David is
17 to 15
Problem 3 :
Find the ratio of the age of David to John.
Solution :
Age of David = 15 years
Age of John = 17 years
Age of David : Age of John = 15 : 17
Hence, the ratio of the age of David to John is
15 to 17
Problem 4 :
Find the ratio of the weight of David to John.
Solution :
Weight of David = 29 kg
Weight of John = 31 kg
Weight of David : Weight of John = 29 : 31
Hence, the ratio of the Weight of David to John is
29 to 31
Problem 5 :
Find the ratio of the height of John to David.
Solution :
Height of John is
= 1m + 36cm
= 100cm + 36cm
= 136 cm
Height of David = 123 cm
Height of John : Height of David = 136 : 123
Hence, the ratio of the height of John to height of David is
136 to 123
Problem 6 :
Find the ratio of studying time of John to David.
Solution :
Studying time of John is
= 4 hours
= 4 ⋅ 60 min
= 240 minutes
Studying time of David = 180 minutes
Studying time --> John : David = 240 : 180
Studying time --> John : David = 4 : 3
Hence, the ratio of studying time of John to David is
4 to 3
Problem 7 :
Find the ratio of speed of cycling between John and David.
Solution :
Speed of cycling of John = 10 kmph
Speed of cycling of David = 15 kmph
Speed of cycling --> John : David = 10 : 15
Speed of cycling --> John : David = 2 : 3
Hence, the ratio of speed of cycling between John and David is
2 to 3
Problem 8 :
Find the ratio of playing time of John to David.
Solution :
Playing time of John = 2 hours
Playing time of David = 1 hour
Playing time --> John : David = 2 : 1
Hence, the ratio of playing time of John to David is
2 to 1
Problem 9 :
A student has 12 note books and 8 text books. Find the ratio of the note books to text books.
Solution :
No. of note books = 12
No. of textbooks = 8
No. of note books : No. of textbooks = 12 : 8
No. of note books : No. of textbooks = 3 : 2
Hence, the ratio of notebooks to textbooks is
3 to 2
Problem 10 :
The cost of a pen is $3 and the cost of pencil is $1.50. Find the ratio of the cost of a pen to pencil.
Solution :
Cost of a pen = $3 = 3 ⋅ 100 = 300 pennies
Cost of a pencil = $1.50 = 1.50 ⋅ 100 = 150 pennies
Cost of a pen : Cost of a pencil = 300 : 150
Cost of a pen : Cost of a pencil = 2 : 1
Hence, the ratio of cost of a pen to pencil is
2 to 1
(From problem no. 11 to problem no.13, please use the information given below)
In a Village of 10,000 people, 4,000 are Government Employees and the remaining are self-employed.
Problem 11 :
Find the ratio of the government employees to people of the village.
Solution :
No. of government employees = 4000
Total no. of people in the village = 10000
Government employees : Village people = 4000 : 10000
= 2 : 5
Hence, the ratio of government employees to village people is
2 to 5
Problem 12 :
Find the ratio of self employed to people of the village.
Solution :
No. of self employed is
= 10000 - 4000
= 6000
Total no. of people in the village = 10000
Self employed : Village people = 6000 : 10000
= 3 : 5
Hence, the ratio of self employed to village people is
3 to 5
Problem 13 :
Find the ratio of self employed to government employees.
Solution :
No. of self employed is
= 10000 - 4000
= 6000
No. of government employees = 4000
Self employed : Government employees = 6000 : 4000
Self employed : Government employees = 3 : 2
Hence, the ratio of self employed to government employees is
3 to 2
After having gone through the stuff given above, we hope that the students would have understood, how to solve problems on ratio and proportion.
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