# Question1 and 2

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In this page question1 and 2 we are going to see solution for question 1 and 2.

**Question 1:**

Martin
is four times as old as his brother Luther at present. After 10 years
he will be twice the age of his brother. Find their present ages.

**Solution**

Let "X" be the present age of Luther

Martin's age = 4 x Luther's age

Martin's age = 4 X

After 10 years the age of Luther will be (x + 10) and the age of Martin will be 4x + 10.

then

4 x + 10 = 2 (x + 10)

4 x + 10 = 2 x + 20

4x - 2x = 20 - 10

2x = 10

x = 5

Age of Luther = 5 years

Age of Martin = 4 x 5

= 20 years

So the correct option is **(B) 5 years and 20 years**

**Question 2:**

A
father is 30 years older than his son,and one year ago he was four
times as old as his son. Find the present ages of his father and his
son.

**Solution**

Let "X" be the son's present age

Father's present age = x + 30

One year ago son's age = x - 1

One year ago father's age = x + 30 - 1

= x + 29

father's age = 4 x age of son

x + 29 = 4 (x-1)

x + 29 = 4x - 4

x - 4x = - 4 - 29

- 3x = -33

x = 33/3

x = 11

Present age of son = 11 years

present age of father = x + 30

= 11 + 30

= 41 years

So the correct option is **(A) 11 years and 41 years**

Question1 and 2 to Worksheet