In this page NCERT solutions for class 10 maths chapter 3 part 5 you can find solutions for exercise problems.
(5) Half the perimeter of a rectangular garden,whose length is 4 m more its width,is 36 m. Find the dimensions of the garden.
Solution:
Let "x" be the width of the rectangular garden
Let "y" be its length
y = x + 4 -------- (1)
Half the perimeter of the rectangular garden = 36 m
perimeter of rectangle = 2 (L + b)
L + b = 36
y + x = 36
y = 36 - x -------- (2)
The point of intersection of those two lines is (16,20). So,length of the rectangular garden is 20 m and width of the rectangular garden is 16 m.
(6) Given the linear equation 2 x + 3 y - 8 = 0,write another linear equation in two variables such that the geometrical representation of the pair so formed is:
Solution:
(i) intersecting lines
The condition for intersection of two lines is a₁/a₂ ≠ b₁/b₂.According to the above condition,we have to form a equation.
a₁ = 2 b₁ = 3 c₁ = -8
The values of a₂,b₂ and c₂ be any real values but the simplified values of a₁/a₂ and b₁/b₂ shouldn't be equal.
a₂ = 3 b₂ = -3 c₂ = -16
So one of the possible required equation is 3 x - 3 y - 16 = 0.
(ii) Parallel lines
The condition for two parallel lines is a₁/a₂ = b₁/b₂ ≠ c₁/c₂.According to the above condition,we have to form a equation.
a₁ = 2 b₁ = 3 c₁ = -8
if the value of a₂ is 4,the value of b₂ will be 6. The value of c₂ must be any value other than -16.
a₂ = 4 b₂ = 6 c₂ = 6
So one of the possible required equation is 4 x + 6 y - 6 = 0.
(iii) Coincident lines
The condition for coincident lines is a₁/a₂ = b₁/b₂ = c₁/c₂.According to the above condition,we have to form a equation.
a₁ = 2 b₁ = 3 c₁ = -8
the values of a₂,b₂ and c₂ will be
a₂ = 4 b₂ = 6 c₂ = -16
So one of the possible required equation is 4 x + 6 y - 16 = 0.
(7) Draw the graphs of the equations x - y + 1 = 0 and 3 x + 2 y - 12 = 0. Determine the coordinates of the vertices of the triangle formed be these lines and the x-axis and shade the triangular region.