Mixed Word problem7

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Question:

Maria worked 5 ½ hours on Tuesday and 6 ¼ hours on Wednesday. John worked 2 ½ on Tuesday and 5 ¼ hours on Wednesday.How many fewer hours did John work?

Basic idea:

In this problem two persons are working Maria and John.Now we need to find how many fewer hours did John work.To solve this problem first we have to find total working hours of Maria and also total working hours for John.Then we have to subtract them to find the difference.

Solution:

Time taken by Maria  = 5 ½ + 6 ¼

                             = (10+1)/2 + (24+1)/4

                             =  11/2 + 25/4

                             =  (11/2)x(2/2) + 25/4

                             =  22/4 +  25/4

                             =  (22+25)/4

                             =  47/4 

         
Time taken by John  = 2
½ + 5 ¼

                            = (4+1)/2 + (20+1)/4

                            = (5/2) + (21/4)

                            = (5/2)x(2/2) + 21/4

                            = (10/4) + (21/4)

                            = (10+21)/4

                            =  31/4

Difference of time taken between  Maria and John = 47/4 - 31/4              

                                                                    = (47-31)/4

                                                                    = 16/4

                                                                    =  4 hours 

Maria had worked 4 hours fewer than John.




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