# Mixed Word problem7

In this page mixed word problem7 you can find the question as well as solution for this question with detailed explanation.Like this you can see every problems with detailed solution and explanation.

Question:

Maria worked 5 ½ hours on Tuesday and 6 ¼ hours on Wednesday. John worked 2 ½ on Tuesday and 5 ¼ hours on Wednesday.How many fewer hours did John work?

Basic idea:

In this problem two persons are working Maria and John.Now we need to find how many fewer hours did John work.To solve this problem first we have to find total working hours of Maria and also total working hours for John.Then we have to subtract them to find the difference.

Solution:

Time taken by Maria  = 5 ½ + 6 ¼

= (10+1)/2 + (24+1)/4

=  11/2 + 25/4

=  (11/2)x(2/2) + 25/4

=  22/4 +  25/4

=  (22+25)/4

=  47/4

Time taken by John  = 2
½ + 5 ¼

= (4+1)/2 + (20+1)/4

= (5/2) + (21/4)

= (5/2)x(2/2) + 21/4

= (10/4) + (21/4)

= (10+21)/4

=  31/4

Difference of time taken between  Maria and John = 47/4 - 31/4

= (47-31)/4

= 16/4

=  4 hours

Maria had worked 4 hours fewer than John.

Mixed Word Problem7 to Worksheets 