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The total weight of 4 girls is 155 ⅕
. If three of them weighs 20
⅕ kg,44
½ kg, and 30 ⅓ kg.Find the weight o the remaining girl.

Basic idea:

In this problem we have total weight of 4 girls that is 155 ⅕ .If the weight of three girls is 20 ⅕ kg,44 ½ kg, and 30 ⅓ kg.Now we need to find the weight o the remaining girl.So let u consider the weight of the remaining girl is x.If we add the given three weights with x we will get 155 ⅕ .Then we can easily solve for x.

Total weight of 4 girls = 155 ¼

Sum of the weight of three girls = (20
⅕ + 44
½ + 30 ⅓ )

= (100+1)/5 + (88+1) /2 + (90+1)/3.

= 101/5 + 89/2 + 91/3

The denominators of the three fractions are not same.So we have to take L.C.M

Here L.C.M is 5 x 2 x 3 = 30

= (101/5) x (6/6) + (89/2) x (15/15) + (91/3) x(10/10)

= 606/30 + 1335/30 + 910/30

= (505 + 1335 + 910) / 30

= 2851 /30

Weight of remaining girl = 155 ⅕
- 2851 /30

= (620+1) /5 - 2851/30

= 621/5 - 2851/30

L.C.M = 30

= (606/5) x (6/6) -(2851/30)

= (3636 -2851)/30

= 785/30

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