# Mixed Word Problem3

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Question:

A man's monthly salary is \$ 800. From this he spends 305 ¾ for food and \$ 100 ½ for children's education. How much will remaining with him?

Basic idea:

In this problem a man's monthly salary is \$ 800. From this he is spending 305 ¾ for food and \$ 100 ½ for children's education. Now we need to find how much will remaining with him.To solve this problem we have to add the amount spent for food and amount spent for children's education.Then we have to subtract them from the salary 800.

Solution:

Monthly salary of a man = 800

Amount spent for food = \$305
¾

Amount spent for education = \$100 ½

Remaining money = 800 - (305
¾ +  100 ½)

First we have to change the mixed fraction as improper fraction.

= 800 - [ (1220+3)/4 + (200+1)/2 ]

= 800 - [ (1223/4)  + (201/2)]

Now we have to take L.C.M for 2 and 4.Here L.C.M is 4

= 800 - [ (1223/4)  + (201/2) x (2/2) ]

= 800 - [(1223/4) + (402/4)]

= 800 - [ (1223+402) /4 ]

=  800 - 1625/4

=  (800/1) - (1625/4)

Here L.C.M for 1 and 4 is 4

=  (800/1) x (4/4) - (1625/4)

=  (3200/4) - (1625/4)

=   1575/4

So a person will have \$ 393.75 in his salary.

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