# Mixed Word Problem1

In this page mixed word problem1 you can find the question as well as solution for this question with detailed explanation.Like this you can see every problems with detailed solution and explanation.

Question:

A can contains 10 kg of oil.2 ¾ kg and 5 ⅓  kg are poured into two vessels. How much is left in the can?

Basic idea:

In this problem a can is containing 10 kg of oil .In that 2 ¾ kg and 5  ⅓  kg are poured into two vessels. Now we need to find how much is left in the can.To solve this problem we have find the total quantity of oil which had poured into two vessels.And then we have to subtract them with the original quantity of oil.

Solution:

Quantity of oil originally = 10 kg

Quantity of oil poured into the vessels  = 2 ¾ + 5 ⅓

Remaining quantity of oil = Original quantity of oil - Quantity of oil poured

= 10 - (2 ¾ + 5 ⅓)

First we have to change these mixed fraction as improper fraction

=  10 - [(8+3)/4 + (15+1)/3]

=  10 - [(11/4) + (16/3)]

Let us take L.C.M for the fractions which is inside the bracket

Here L.C.M for 4 and 3 is 12.To make 4 as 12 we have to multiply them by 3.And to make 3 as 12 we have to multiply them by 4.

=  10 - [(11/4) x (3/3) + (16/3) x (4/4)]

=  10 - [(33/12 ) + (64/12)]

=  10 - [(33 + 64)/12]

=  10- [97/12]

= (10/1) - (97/12)

again we have to take L.C.M

Here L.C.M for 1 and 12 is 12.

=  (10/1) x(12/12) - (97/12)

=  (120/12) - (97/12)

=  (120-97)/12

=   23/12

Therefore quantity of oil left in the can is  23/12 kg.

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