In this page lcm practical problems question2 we are going to see solution of first problem.
Three boy start running round a circular track in a sports stadium. They start at the same time and run in the same direction. The first boy takes 10 minutes,the second boy takes 12 minutes and the third boy takes 15 minutes to go round once. After how many minutes will they be together again? How many rounds would each run before they are together again?
There are three boys running in a circular track starting at the same point and running in the same direction.First,second and third boys are taking 10 minutes,12 minutes and 15 minutes respectively to go round once. From this we need to find After how many minutes will they be together again. For that we have to take L.C.M Otherwise we can write 10 times table ,12 times table and 15 times table separately and find out which least number we got. Since this is the lengthy method we are going to choose the first method. That is taking L.C.M
10 = 5 x 2
12 = 2 x 2 x 3
15 = 5 x 3
L.C.M = 2 x 2 x 5 x 3
After 60 minutes the three boys are meet together
The first boy is taking 10 minutes to round once the ground.
Number of times run by the first boy = 60/10 = 6 rounds
The second boy is taking 12 minutes to round once the ground.
Number of times run by the second boy = 60/12 = 5 rounds
The third boy is taking 15 minutes to round once the ground.
Number of times run by the third boy = 60/15 = 4 rounds
lcm practical problems question2 lcm practical problems question2