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Radius is the distance between center and one of the vertex.
Area of regular polygon = 1/2 x Perimeter x Apothem
Perimeter = Sum of length of all sides
Apothem is the perpendicular distance between center and one of the sides.
Find the area of each polygon with given radius. Leave the answer in radical.
Problem 1 :

Solution :
Number of sides of the polygon = 4

∠AOB = 360/4 ==> 90
∠COB = 90/2 ==> 45
OB = Radius = 6 cm
In triangle COB,
|
sin θ = BC / OB sin 45 = BC / 6 1/√2 = BC / 6 BC = 6/√2 BC = 3√2 |
tan θ = BC / OC tan 45 = 3√2 / OC 1 = 3√2 / OC OC = 3√2 |
AB = 2 BC ==> 2(3√2) ==> 6√2
Area of regular polygon = 1/2 x Perimeter x Apothem
Perimeter = 4 (6√2) ==> 24√2
Area of polygon = (1/2) x 24√2 x 3√2
= 72 cm2
Problem 2 :

Number of sides of the polygon = 3
radius = 18
∠AOB = 360/3 ==> 120
∠COB = 120/2 ==> 60
OB = 18 (radius)
In triangle OCB,
|
sin θ = BC / OB sin 60 = BC / 18 √3/2 = BC / 18 BC = 9√3 |
tan θ = BC / OC tan 60 = 9√3 / OC √3 = 9√3 / OC OC = 9 Apothem = 9 |
AB = 2(9√3) ==> 18√3
Area of regular polygon = 1/2 x Perimeter x Apothem
Perimeter = 3(18√3) ==> 54√3
Area of regular polygon = 1/2 x 54√3 x 9
= 243√3
Problem 3 :

Solution :

Number of sides of the polygon = 6
radius = 8
∠AOB = 360/6 ==> 60
∠COB = 60/2 ==> 30
OB = 8 (radius)
In triangle OCB,
|
sin θ = BC / OB sin 30 = BC / 8 1/2 = BC / 8 BC = 4 |
tan θ = BC / OC tan 30 = 4 / OC 1/√3 = 4 / OC OC = 4√3 Apothem = 4√3 |
AB = 2(4) ==> 8
Area of regular polygon = 1/2 x Perimeter x Apothem
Perimeter = 6(8) ==> 48
Area of regular polygon = 1/2 x 48 x 4√3
= 96√3
Problem 4 :
A regular nonagon has a perimeter 45 inches and its apothems are each 6 9/10 inch long.
a) Find the area
b) Round the length of an apothem to the nearest inch and find the area. How does it compare to the original area ?
Solution :
Perimeter = 45 inches
Length of apothem = 6 9/10 inch ==> 69/10
= 6.9 inches
Approximately 7 inches
Number of sides of nonagon = 9
9(side length of nonagon) = 45
Side length of nonagon = 45/9
= 5
a) Area of nonagon
= (1/2) x perimeter x apothem
= (1/2) x 45 x 6.9
= 155.25 square inches
b) Area of nonagon
= (1/2) x perimeter x apothem
= (1/2) x 45 x 7
= 157.5 square inches
After rounding the length of apothem for the nearest integer, the new area is 2.25
Problem 5 :
The area of a regular octagon is 392.4 square meters, and an apothem is 10.9 meters long
a) Find the perimeter
b) Find the length of one side.
Solution :
Area of octagon = 392.4 square meter
Length of apothem = 10.9 meter
Number of sides of octagon = 8
(1/2) x perimeter x apothem = 392.4
(1/2) x perimeter x 10.9 = 392.4
Perimeter = 392.4/5.45
= 72
a) So, the perimeter of the octagon is 72 meter.
b) Number of sides x measure of one side = 8(9)
Side length of the octagon = 9 meter
Problem 6 :
Find the approximate area of Fort Jefferson in Dry Tortugas National Park, Florida, if each side is 460 feet long and an apothem is about 398 feet long.

Solution :
Number of sides of the fort = 6
Measure of each side = 460 feet
Apothem = 398 feet
Area of fort = (1/2) x 6(460) x 398
= 3 x 460 x 398
= 549240 square feet
Problem 7 :
The petals in the flower form a polygon that is approximately a regular pentagon with an apothem 3.4 cm long.
a) Find the approximate area of the pentagon.
b) There are five triangles in the pentagon that are not part of the flower. Assume that they have equal areas and have a height of 1.5 cm. Find the total area of triangles.
c) What is the approximate area of the flower.

Solution :
a) Area of pentagon = (1/2) x perimeter x apothem
perimeter of pentagon = 5(5)
= 25 cm
Apothem = 3.4 cm
Area of pentagon = (1/2) x 25 x 3.4
= 42.5 square meter
b) Area of triangle = (1/2) x base x height
base = 5 cm and height = 1.5 cm
= (1/2) x 5 x 1.5
= 2.5 x 1.5
= 3.75 square meter
Area of 5 triangles = 5(3.75)
= 18.75 square meter
c) Area of flower = area of pentagon - 5 x area of triangle
= 42.5 - 18.75
= 23.75 square meter

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