FIND THE MISSING VALUE IN EACH PROPORTION WORKSHEET

Problem 1 :

Find the missing value in the given proportion.

(i)  2 : 5  =  6 : x

(ii)  16 : 20  =  x : 35

(iii)  3 : 4  =  6 : x

(iv)  3 : 6  =  12 : x

(v)  2 : 5  =  x : 15

(vi)  7 : 21  =  x : 33

(vii)  15 : 25  =  30 : x

(viii)  x : 18  =  32 : 48

(ix)  5 : 100  =  x : 40

(x)  x : 12  =  33 :  44

Problem 2 :

A disaster relief team consists of engineers and doctors in the ratio of 2 : 5.

a) If there are 18 engineers, find the number of doctors.

b) If there are 65 doctors, find the number of engineers

1. Answer :

(i)  2 : 5  =  6 : x

Product of extremes  =  Product of means

2x  =  5(6)

2x  =  30

x  =  15

(ii)  16 : 20  =  x : 35

16(35)  =  20x

x  =  16(35)/20

x  =  28

(iii)  3 : 4  =  6 : x

3x  =  4(6)

x  =  24/3

x  =  8

(iv)  3 : 6  =  12 : x

3x  =  6(12)

x  =  72/3

x  =  24

(v)  2 : 5  =  x : 15

2(15)  =  5x

x  =  30/5

x  =  6

(vi)  7 : 21  =  x : 33

7(33)  =  21x

x  =  7(33)/21

x  =  11

(vii)  15 : 25  =  30 : x

15(x)  =  25(30)

x  =  25(30)/15

x  =  50

(viii)  x : 18  =  32 : 48

x(48)  =  18(32)

x  =  18(32)/48

x  =  12

(ix)  5 : 100  =  x : 40

5(40)  =  100x

x  =  5(40)/100

x  =  2

(x)  x : 12  =  33 :  44

x(44)  =  12(33)

x  =  12(33)/44

x  =  9

2. Answer :

Let 2x and 5x are number of engineers and doctors respectively.

(a)  Number of engineers  =  18

2x  =  18

x  =  9

Number of doctors  =  5x

=  5(9)

=  45

b) If there are 65 doctors, find the number of engineers

Number of doctors  =  65

5x  =  65

x  =  65/5

x  =  13

Number of engineers  =  2x

=  2(13)

=  26

Number of engineers is 26.

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