EXPAND ALGEBRAIC EXPRESSIONS WITH BRACKETS
About "Expand algebraic expressions with brackets"
On this webpage "Expand algebraic expressions with brackets", we are going to see how to multiply two or more polynomials with step by step explanation.
How to expand and simplify brackets
We will multiply two or more polynomials in the following order.
(1) Symbol
(2) Number
(3) Variable
Let us see how it works
Multiply ( 5 x² ) and (-2 x³)
= ( 5 x² ) x (-2 x³)
= 10 x⁵
More examples of expanding algebraic expressions with brackets
Problem 1 :
Multiply ( - 6 x ) and (- 4 x³)
Solution :
= ( - 6 x ) x (- 4 x³)
= 24 x⁴
let us see the next example on "Expand algebraic expressions with brackets"
Problem 2 :
Multiply (2 a - 1) and (8 a - 5)
Solution :
= (2 a - 1) (8 a - 5)
To multiply these binomials we have to distribute 2 a with (8 a - 5) and distribute -1 with (8 a - 5)
When we combine the like terms,we get
= 16 a² - 18 a + 5
We can do the the same problem in the following flow chart method also.
When we combine the like terms,we get
= 16 a² - 18 a + 5
let us see the next example on Expand algebraic expressions with brackets"
Problem 3 :
Multiply (2 a² + 5 a - 1) x (8 a² - 3 a + 5)
Solution :
= (2 a² + 5 a - 1) x (8 a² - 3 a + 5)
To multiply these trinomials we have to distribute 2 a² with (8 a² - 3 a + 5), distribute 5 a with (8 a² - 3 a + 5) and -1 with (8 a² - 3 a + 5).
= 16a⁴-6 a³+10 a²+40 a³-15 a²+25 a-8 a²+3 a-5
Now we have to combine the like terms
= 16a⁴-6a³+40a³+10a²-15a²-8a²+25a+3a-5
= 16a⁴ + 34 a³ -13 a²+ 28 a - 5
let us see the next example on "Expand algebraic expressions with brackets"
Problem 4 :
Multiply (2 x² + 5) and (3y² - 4 y + 7)
Solution :
= (2 x² + 5) x (3y² - 4 y + 7)
To multiply these binomial and trinomial we have to distribute 2 x² with (3y² - 4 y + 7) and distribute 5 with (3y² - 4 y + 7)
= 6 x²y² - 8 x² y + 14 x²+ 1 5 y² - 40 y + 35
now we have to combine the like terms
= - 2 x² y + 14 x²+ 1 5 y² - 40 y + 35
Now let us see another problem in multiplication of polynomials.
let us see the next example on "Expand algebraic expressions with brackets"
Problem 5 :
Multiply (3 x + 8) and (4y - 7)
Solution :
= (3 x + 8) x (4y - 7)
To multiply these binomials we have to distribute 3x with (4y - 7) and distribute 8 with (4y - 7)
= 12 x y -21 x + 32 y - 56
Since there is no like terms.So we cannot simplify this.
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