## Elimination Method Questions 1

In this page elimination method questions 1 we are going to see solution of first problem from the worksheet elimination method worksheet.

Question 1

Solve the following system of linear equations by elimination-method

x + 2 y = 7,x – 2 y = 1

Solution:

X + 2 y = 7    --------- (1)

X – 2 y = 1   --------- (2)          elimination method questions 1

There are two unknowns in the given equations. From these equations we have to find the values of x and y. For that let us consider the coefficients of x and y in both equation. In the first equation we have + 2y and in the second equation we have -2y and the symbols are not same so we can easily eliminate the variable y by just adding two equations.

Adding (1) and (2) we get

X + 2 y = 7

X – 2 y = 1

-------------

2x = 8

x = 8/2

x = 4

now we have to apply the value of x in wither given equations to get the value of another variable y

Substitute x = 4 in the first equation we get

4 + 2 y = 7

2 y = 7 – 4

2 y = 3

y = 3/2

Solution:

x = 4

y = 3/2

verification:

x  + 2 y = 7

4 + 2(3/2)= 7

4 + 3 = 7

7 = 7                elimination method questions 1

## Need to try other questions:

Solve each of the following system of equations by elimination method.

• 3 x + y = 8 , 5 x + y = 10    Solution
• x + y/2 = 4 , x / 3 + 2 y = 5   Solution
• 11 x - 7 y = x y , 9 x - 4 y = 6 x y   Solution
• 3/y + 5/x = 20/x y , 2/x + 5/ y = 15/x y   Solution
• 8 x – 3 y = 5 x y , 6 x – 5 y = -  2 x y    Solution
• 13 x+ 11 y = 70 ,11 x + 13 y = 74     Solution
• 65 x – 336 y = 97 , 33 x – 65 y = 1     Solution
• 15/ x + 2/y = 17 , 1/x + 1/y = 36/5  Solution
• 2/x + 2/3y  = 1/6,3/x + 2/y = 0    Solution