Elimination Method Questions 1





In this page elimination method questions 1 we are going to see solution of first problem from the worksheet elimination method worksheet.

Question 1

Solve the following system of linear equations by elimination-method

x + 2 y = 7,x – 2 y = 1 

Solution:

X + 2 y = 7    --------- (1)

X – 2 y = 1   --------- (2)          elimination method questions 1

There are two unknowns in the given equations. From these equations we have to find the values of x and y. For that let us consider the coefficients of x and y in both equation. In the first equation we have + 2y and in the second equation we have -2y and the symbols are not same so we can easily eliminate the variable y by just adding two equations.

Adding (1) and (2) we get

                 X + 2 y = 7    

                X – 2 y = 1  

              -------------

                2x = 8                           

                  x = 8/2

                  x = 4

now we have to apply the value of x in wither given equations to get the value of another variable y

Substitute x = 4 in the first equation we get

     4 + 2 y = 7

            2 y = 7 – 4

             2 y = 3

               y = 3/2       

Solution:

     x = 4

     y = 3/2    

verification:

 x  + 2 y = 7

 4 + 2(3/2)= 7

 4 + 3 = 7 

 7 = 7                elimination method questions 1

Need to try other questions:

Solve each of the following system of equations by elimination method.

  • 3 x + y = 8 , 5 x + y = 10    Solution
  • x + y/2 = 4 , x / 3 + 2 y = 5   Solution
  • 11 x - 7 y = x y , 9 x - 4 y = 6 x y   Solution
  • 3/y + 5/x = 20/x y , 2/x + 5/ y = 15/x y   Solution
  • 8 x – 3 y = 5 x y , 6 x – 5 y = -  2 x y    Solution
  • 13 x+ 11 y = 70 ,11 x + 13 y = 74     Solution
  • 65 x – 336 y = 97 , 33 x – 65 y = 1     Solution
  • 15/ x + 2/y = 17 , 1/x + 1/y = 36/5  Solution
  • 2/x + 2/3y  = 1/6,3/x + 2/y = 0    Solution


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