## Division word problem5

In this page we are going to see division word problem5.You can find question as well as the solution for the problem.We have given clear explanation of each step.We hope that this page will be very useful to the students who are studying in school.Like this problem you can find many problems with detailed solution in this site.

Question:

The product of two fractions is 30 ⅓. One of them is 5 ⅔.  Find the other?

Basic idea:

In this problem we have the product of two fractions that is 30 ⅓.One of the number is given that is 5 ⅔. We need to find the other number.To solve this problem we need to assign the other fraction as x.By multiplying  5 ⅔ with x we will get 30 ⅓.We can solve for x by dividing 30 ⅓ by 5 ⅔.

Let the required second fraction be "X"

One of the fraction  =  5 ⅔

Product of two fractions = 30 ⅓

5 ⅔ x X  = 30 ⅓

Now we have to change the mixed fraction as improper fraction

(15+2)/3 x X = (90+1)/3

(17/3) x X = 91/3

X = 91/3 ÷ (17/3)

Now we are going to change this division as multiplication.So that we have to write the second fraction as its reciprocal.The first fraction has to be written as it is.

X = (91/3) x (3/17)

X = (91x3)/(3x17)

The numerator and denominator 3 can be simplified using 3 times table.

X =  91/17

So the final answer is  91/17 .

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