## Arithmetic Sequence Worksheet Solution5

**Online Math Tutoring by Expert Indian Math Tutor**

**ACT, SAT, Pre SAT, SCAT, SHSAT, ISEE and More.**

**Tutoring Charges $10 per hour**

**No credit card required**

**Free demo for 30 minutes**

**Mail us : v4formath@gmail.com **

**Skype id : rams_tpt**

**Mobile : +919994718681**

In the page arithmetic sequence worksheet solution5
you are going to see solution of each questions from the arithmetic sequence
worksheet.

(15) If m times the mth term
of an A.P is equal to the n times the nth term, then show that the (m + n)th
term of the A.P is zero

**Solution:**

m tm = n tn

m [ a+ (m - 1) d ] = n [ a+
(n - 1) d ]

m a + m d (m – 1) = n a + n d (n – 1)

m a + m² d – m d = n a + n² d – n d

m a - n a + m² d - n² d –
m d + n d = 0

a (m – n) + (m² - n² – m +
n ) d = 0

a (m – n) + [ (m + n) (m -
n) –( m - n ) ] d = 0

a (m – n) + (m – n) [ (m +
n) – 1 ] d = 0

Divide by (m - n) => a +
[ (m + n) – 1 ] d = 0

t (m + n)
= 0

Therefore the (m+n) th term
of the A.P is zero.

(16) A person has deposited
$25000 in an investment which yields 14% simple interest annually. Do these
amounts (principal + interest) form an A.P? If so, determine the amount of
investment after 20 years.

**Solution:**

Simple interest = PNR/100

= (25000 x 1 x 14)/100

= 3500

Amount = principal +
interest

= 25000 + 3500

= 28500

Amount at the end of the
first year = 28500

Amount at the end of second
year = 28500 + 3500

= 32000

Amount at the end of third
year = 32000 + 3500

= 35500

28500,32000,35500.,………………….

This is the arithmetic
sequence. To find the amount of investment after 20 years we need to find 20th
term

tn = a +(n - 1) d

a = 28500 d = 32000 – 28500

= 3500

t20 = 28500 + (20 - 1) 3500

= 28500 + 19 (3500)

= 28500 + 66500

= 95000

arithmetic sequence worksheet solution5 arithmetic sequence worksheet solution5