AREA OF TRIANGLE WORKSHEETS

About "Area of triangle worksheets"

Area of triangle worksheets :

Here we are going to see some practice questions based on the topic area of triangle.

Area of triangle worksheets - Practice questions

(1)  Find the area of triangle whose vertices are (6,7) (2,-9) and (-4,1).

(2)  Find the area of triangle whose vertices are (3,4) (2,-1) and (4,-6).

(3)  Find the area of triangle whose vertices are (5,6) (2,4) and (1,-3).

(4)  Find the area of triangle whose vertices are (1,3) (-7,6) and (5,-1).

(5)  Find the area of triangle whose vertices are (1,1) (3,4) and (5,-2).

(6)  Find the area of triangle whose vertices are (-3,-9) (-1,6) and (3,9).

(7)  Find the area of triangle whose vertices are (-3,-9) (3,9) and (5,-8).

(8)  Find the area of triangle whose vertices are (4,5) (4,2) and (-2,2).

(9)  Find the area of triangle whose vertices are (3,1) (2,2) and (2,0).

(10)  Find the area of triangle whose vertices are (3,1) (0,4) and (-3,1).

Area of triangle worksheets - Solution

Question 1 : 

Find the area of triangle whose vertices are (6,7) (2,-9) and (-4,1).

Solution :

Now we have to take anticlockwise direction. So, we have to take the points in the order A (6,7) C (-4,1) and B (2,-9)

x₁ = 6     x₂ = -4      x₃ = 2

y₁ = 7     y₂ = 1       y₃ = -9

Area of the triangle ACB 

  =  (1/2) {(6 + 36 + 14) - (-28 + 2 - 54)}

  =  (1/2) {56 - ( -82 + 2)}

  =  (1/2) {56 - (-80) }

  =  (1/2) {56 + 80)}

  =  (1/2)  x 136 

  =  68 Square units.

Hence, the area of  ACB  =  68 square units.

Question 2 :

Find the area of triangle whose vertices are (3,4) (2,-1) and (4,-6).

Solution :

Now we have to take anticlockwise direction. So, we have to take the points in the order A (6,7) C (-4,1) and B (2,-9)

x₁ = 3     x₂ = 2         x₃ = 4

y₁ = 4     y₂ = -1        y₃ = -6

Area of the triangle ACB 

  =  (1/2) {(-3 - 12 + 16) - (8 - 4 - 18)}

  =  (1/2) {(-15 + 16) - (8 - 22)}

  =  (1/2) {1 - (-14) }

  =  (1/2) x (1 + 14)

  =  (1/2)  x 15 

  =  15/2  =  7.5 Square units.

Hence, the area of  ABC  =  7.5 square units.

Question 3 :

Find the area of triangle whose vertices are (5,6) (2,4) and (1,-3).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order A (5,6) B (2,4) and C (1,-3)

x₁ = 5     x₂ = 2        x₃ = 1

y₁ = 6     y₂ = 4       y₃ = -3

Area of the triangle ABC 

  =  (1/2) {(20 - 6 + 6) - (12 + 4 - 15)}

  =  (1/2) {20 - (16 - 15)}

  =  (1/2) {20 - (1) }

  =  (1/2) {20 - 1}

  =  (1/2)  x 19 

  =  19/2  ==>  9.5 Square units.

Hence, the area of  ABC  =  9.5 square units.

Question 4 : 

Find the area of triangle whose vertices are (1,3) (-7,6) and (5,-1).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order A (1,3) B (-7,6) and C (5,-1)

x₁ = 1     x₂ = -7      x₃ = 5

y₁ = 3     y₂ = 6       y₃ = -1

Area of the triangle ACB 

  =  (1/2) {(6 + 7 + 15) - (-21 + 30 - 1)}

  =  (1/2) {28 - ( -22 + 30)}

  =  (1/2) {28 - (8) }

  =  (1/2) {28 - 8}

  =  (1/2)  x 20 

  =  10 Square units.

Hence, the area of  ABC  =  10 square units.

Question 5 :

Find the area of triangle whose vertices are (1,1) (3,4) and (5,-2).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order B (3,3) A (1, 1) and C (5,-2)

x₁ = 3     x₂ = 1      x₃ = 5

y₁ = 3     y₂ = 1       y₃ = -2

Area of the triangle BAC 

  =  (1/2) {(4 - 6 + 5) - (3 + 20 - 2)}

  =  (1/2) {(9 - 6) - (23 - 2)}

  =  (1/2) {3 - 21}

  =  (1/2) {-18}

  =  -18/2 

  =  9 Square units.

Hence, the area of  ABC  =  9 square units.

Question 6 :

Find the area of triangle whose vertices are (-3,-9) (-1,6) and (3,9).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order C (3,9) B (-1,6) and A (-3,-9)

Area of the triangle CBA 

  =  (1/2) {(18 + 9 - 18) - (-9 - 18 - 27)}

  =  (1/2) {9 - ( -54)}

  =  (1/2) {9 + 54}

  =  (1/2) (63)

  =  (63/2) 

  =  31.5 Square units.

Hence, the area of CBA  =  31.5 square units.

Let us see the solution of next problem on "Area of triangle worksheets".

Question 7 :

Find the area of triangle whose vertices are (-3,-9) (3,9) and (5,-8).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order B (3,9) A (-3,-9) and C (5,-8)

x₁ = 3     x₂ = -3      x₃ = 5

y₁ = 9     y₂ = -9      y₃ = -8

Area of the triangle BAC 

  =  (1/2) {(-27 - 24 + 45) - (-27 - 45 - 24)}

  =  (1/2) {(-51 + 45) - (-96)}

  =  (1/2) {-6 + 96}

  =  (1/2) (90)

  =  (90/2)

  =  45 Square units.

Hence, the area of  BAC  =  45 square units.

Let us see the solution of next problem on "Area of triangle worksheets".

Question 8 :

Find the area of triangle whose vertices are (4,5) (4,2) and (-2,2).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order A (4,5) C (-2,2) and B (4,2)

x₁ = 4     x₂ = -2      x₃ = 4

y₁ = 5     y₂ = 2       y₃ = 2

Area of the triangle ACB 

  =  (1/2) {(8 - 4 + 20) - (-10 + 8 + 8)}

  =  (1/2) {(28 - 4) - ( -10 + 16)}

  =  (1/2) (24 - 6)

  =  (1/2) x 18

  =  (18/2) 

  =  9 Square units.

Hence, the area of  ACB  =  9 square units.

Let us see the solution of next problem on "Area of triangle worksheets".

Question 9 :

Find the area of triangle whose vertices are (3,1) (2,2) and (2,0).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order B (2,2) C (2,0) and A (3,1)

x₁ = 2     x₂ = 2       x₃ = 3

y₁ = 2     y₂ = 0       y₃ = 1

Area of the triangle BCA 

  =  (1/2) {(0 + 2 + 6) - (4 + 0 + 2)}

  =  (1/2) {8 - 6}

  =  (1/2) (2)

  =  (2/2)

  =  1 Square units.

Hence, the area of  ACB  =  1 square units.

Let us see the solution of next problem on "Area of triangle worksheets".

Question 10 :

Find the area of triangle whose vertices are (3,1) (0,4) and (-3,1).

Solution :

Now we have to take anticlockwise direction. So we have to take the points in the order B (0,4) C (-3,1) and A (3,1)

x₁ = 0     x₂ = -3      x₃ = 3

y₁ = 4     y₂ = 1       y₃ = 1

Area of the triangle BCA 

  =  (1/2) {(0 -3 + 12) - (-12 + 3 + 0)}

  =  (1/2) {9 - ( -12 + 3)}

  =  (1/2) {9 - (-9) }

  =  (1/2) {9 + 9)}

  =  (1/2)  x 18 

  =  9 Square units.

Hence, the area of  BCA  =  9 square units.

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• Family of circles
• Orthogonal circles
• Parabola
• Ellipse

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