**Aptitude Test 5 : **

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Question No.1 Question No.2 Question No.3 Question No.4 Question No.5 Question No.6 Question No.7 Question No.8 Question No.9 Question No.10 |
For each divisor and corresponding remainder, we have to find the difference.
35-25=10 45-35=10 55-45=10 we get the difference 10 (for all divisors and corresponding remainders) Now we have to find the L.C.M of (35,45,55) and subtract the difference from the L.C.M. L.C.M of (35,45,55) = 3465 Hence the required least number = 3465-10 = 3455
Let "x" be the length of each train
Total distance covered to cross each other = Sum of the lengths of the two trains Total distance covered to cross each other = x+x =2x m Relative speeds of the two trains = 46-36 = 10 kmph = 10X5/18 = 25/9 m/sec Distance = Speed X Time 2x = (25/9)X36 m 2x = 100 m x = 50 m Hence, the length of each train is 50 m
Total work = 60 units. (L.C.M of 10,15,20)
work done by the pipe A = 60/10 = 6 units/hr work done by the pipe B = 60/15 = 4 units/hr work done by the pipe C = 60/20 = 3 units/hr (Given:A is open all the time,B and C are open for one hour each alternately) 1st hour: (A+B) = 10 units/hr 2nd hour: (A+C) = 9 units/hr 3rd hour: (A+B) = 10 units/hr 4th hour: (A+C) = 9 units/hr 5th hour: (A+B) = 10 units/hr 6th hour: (A+C) = 9 units/hr When we add the above units, we get the total 57 units. Apart from the 6 hours of operation, to get the total work 60 units, A has to work for half an hour Because in one of hour work of A, we will get 6 units) Hence, time taken to fill the tank = 6.5 hours.
Let "x" be the speed of A . Then speed of B = 7-x
Time taken by A = 24/x Time taken by B = 24/(7-x) Time(A)+Time(B) = 14 hours. 24/x + 24/(7-x) = 14 24(7-x)+24x = 14x(7-x) 14x ^{2}-98x+168=0--->x^{2}-7x+12=0
(x-4)(x-3)=0--->x = 4 and x = 3 Hence, the speed of A and B are 4 kmph and 3 kmph respectively.
From the given information, we have P+Q = 12+Q+R
When we rearrange the above equation, we get P-R = 12+Q-Q P-R = 12 From the above equation, it is very clear that R is 12 years younger to P
Let "x" be the average after 17th inning
(Total run scored in 17 innings)/17 = x Total run scored in 17 innings = 17x ----(1) Average after 16th inning = x-3 (Total run scored in 16 innings)/16 = x-3 Total runs scored in 16 innings = 16(x-3) Total runs scored in 17 innings = 16(x-3)+87 ----(2) From (1) and (2), we get 16(x-3)+87 = 17x Solving the above equation, we get x = 39 Hence the batsman's average after 17th inning is 39.
Let "x" be the speed of the current
Speed upstream = (10-x) kmph Speed downstream = (10+x) kmph From the given information, we have 26/(10+x) = 14/(10-x) 26(10-x) = 14(10+x) 260-26x = 140+14x 40x = 120 x = 120/40 = 3 kmhr Hence the speed of the current is 3 kmph
From the given information,
original of the 1st house = 16x original of the 2nd house = 23x After increment in prices, price of the 1st house = 16x + 10%of16x=16x+1.6x = 17.6x price of the 2nd house = 23x+477 After increment in prices, the ratio of the prices becomes 11:20 Then we have, 17.6x:(23x+477) = 11:20 20(17.6x) = 11(23x+477) 352x = 253x + 5247 99x = 5247 x = 53 Hence original price of the first house = 16X53 = $848
From the given information, we have
Profit on the first part (c) = 8% Profit on the second part (d) = 18% Profit on the whole (mixture) (m) = 14% Rule to find the ratio for producing mixture = (d-m):(m-c) (d-m):(m-c) = (18-14):(14-8) = 4:6 = 2:3 Quantity of the 2nd kind = 1000X3/5 = 600 kg The quantity sold at 18% profit is 600 kg
Let "x" be the price of a chair. Then the price of a table = x+400
4 tables + 6 chairs = 3600 4(x+400) + 6x = 3600 4x+1600+6x = 3600 10x = 2000 ===>x = 200 So, price of a chair = $400 and price of a table = $800 Price of a chair is $400 less than that of the table Percentage = (400/800)X100% = 50% Hence, the price of a chair is 50% less than that of the table. |

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