In this page ACT practice paper1 solution1 we are going to see solution of some practice questions.

**Question 1:**

If x = -2 and y = 3 then find the value of |2 x - 3 y|

**Solution:**

To find the value of |2 x - 3 y| we have to apply the value of x and y in the given statement.

= |2 x - 3 y|

= |2 (-2) - 3 (3)|

= |-4 - 9|

= |-13|

= 13

So the required answer 13.

**Question 2:**

Simplify the following (8 + 5) x (35/5) + 6

**Solution:**

To simplify this we have to use the rule known as "BODMAS" in the topic "order of operation". First we have to consider the symbol bracket or parenthesis.

= (8 + 5) x (35/5) + 6

= 13 x 7 + 6

next we have to multiply

= 91 + 6

finally we have to add

= 97

So the required answer will be 97.

**Question 3:**

54 _562. This number is divisible by 3. Fill in the blank with any least suitable digit.

**Solution:**

Here the given number 54 _562 is divisible by 3. From this we have to fill a suitable number. For that let us remember the condition for a number which is divisible by 3.

Definition:

A number is divisible by 3 if the sum of the digits is divisible by 3.Ex : 363 Here sum of the digits 3 + 6 + 3 = 9 which is divisible by 3.So the whole number will be divisible by 3.

Let us consider the missing number as "x". Let us find the sum of digits

= 5 + 4 + x + 5 + 6 + 2

= 9 + x + 11 + 2

= 22 + x

There is only one number should be placed. If we put 2 instead of x, the sum will become 24. So it will be divisible by 3. If we put 5 instead of x, the sum will become 27. That number also be divided by 3.But we have to put only least number. So we have to choose 2.

**Question 4:**

The weight of an empty bottle is 128.4 gram. It contains a syrup. The weight of the syrup is 156.8 gram. What is the weight of 24 bottles of syrup?

**Solution:**

The weight of an empty bottle = 128.4 gram

weight of the syrup = 156.8 gram

weight of one bottle with syrup = weight of empty bottle + weight of syrup

= 128.4 + 156.8

= 285.2

from this we have to find the weight of 24 bottles

= 24 x 285.2

= 6844.8 grams

So the required weight is 6844.8 grams

ACT practice paper1 solution1 ACT practice paper1 solution1

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